Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
135 comments Page 9 of 14.
Sudhir Joshi said:
1 decade ago
In 10 overs run scored is 250, and in remaining 40 overs to get the total target of 282, remaining runs are 250 as 32 has been scored. Divide 250 by 40 that will be the required run-rate.
Raj said:
1 decade ago
10*3.2 = 32.
40*? = ?
Required = 282.
40*? = ?
Required = 282.
Rashmi said:
1 decade ago
Is there any short cut for this?
If we solve this way like long method, rest of the questions will be pending. Any one suggest me?
If we solve this way like long method, rest of the questions will be pending. Any one suggest me?
Hemanth said:
1 decade ago
First 10 overs they scored 32 runs====3.2*10.
Then we required to score 250 runs to get the score of 282 in 40 overs=======(28232 = 250 in 40 overs).
Therefore: 250/40 = 6.25.
Then we required to score 250 runs to get the score of 282 in 40 overs=======(28232 = 250 in 40 overs).
Therefore: 250/40 = 6.25.
Rituparna Sengupta said:
1 decade ago
Required run-rate = (282-(3.2*10))/40 = 6.25.
Rituparna Sengupta said:
1 decade ago
(282-(3.2*10))/40 = 6.25.
Ako venuh said:
1 decade ago
We Know Run Rate = Runs/overs.
Therefore, in the first 10 overs.
Run Rate = Runs/Overs.
3.2 = Runs/10.
Runs = 3.2*10.
Runs = 32.
Now 32 runs is scored in the first 10 Overs.
Target = 282.
Target = 282-32 = 250.
Run Rate = Target runs/Remaining Overs.
Run Rate = 250/40.
Run Rate = 6.25.
Therefore, in the first 10 overs.
Run Rate = Runs/Overs.
3.2 = Runs/10.
Runs = 3.2*10.
Runs = 32.
Now 32 runs is scored in the first 10 Overs.
Target = 282.
Target = 282-32 = 250.
Run Rate = Target runs/Remaining Overs.
Run Rate = 250/40.
Run Rate = 6.25.
Vasavi said:
1 decade ago
@Apple.
You give example test match in that problem 80*4 = 320 but you tack it as 360?
You give example test match in that problem 80*4 = 320 but you tack it as 360?
Padmashri said:
1 decade ago
RR runs Target-282.
1-10 overs 3.2 32.
11-40 overs ? 250.
RR = Runs/Overs.
RR = 250/40.
Answer: 6.25.
1-10 overs 3.2 32.
11-40 overs ? 250.
RR = Runs/Overs.
RR = 250/40.
Answer: 6.25.
Manish said:
10 years ago
@Ms. Shobhita.
1 over for 6 balls should be getting 1run for every ball is 6 runs for 6 balls. 1 over 6run rate. 10 overs 32 runs. Run rate was 3.25.
32 runs subtracted for target run 282. Remain 250. Balance 40 overs. Every ball get one run reach in 240. Answer is 6.25.
1 over for 6 balls should be getting 1run for every ball is 6 runs for 6 balls. 1 over 6run rate. 10 overs 32 runs. Run rate was 3.25.
32 runs subtracted for target run 282. Remain 250. Balance 40 overs. Every ball get one run reach in 240. Answer is 6.25.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers