Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
135 comments Page 5 of 14.
Ali said:
9 years ago
Thanks @Vinoth M.
Bhargavi said:
9 years ago
A batsman makes a score of 87runs in the 17th inning & thus increases his avg by 3. Find his avg after 17th inning? Can anyone solve this problem?
Renu said:
9 years ago
Super & excellent explanation @Muhundhan.
Shiva said:
9 years ago
Run rate for first 10 overs is 3.20.
So 10 * 3.20=30 runs in 10 overs.
40 * how much gives 250 = ??? so that over all become 280.
So,
check from options 40 * 6.25 = 250
250 + 30 = 280
Option A is correct answer.
So 10 * 3.20=30 runs in 10 overs.
40 * how much gives 250 = ??? so that over all become 280.
So,
check from options 40 * 6.25 = 250
250 + 30 = 280
Option A is correct answer.
Ritesh bajaj said:
9 years ago
Why we subtract 282 from (3.2*10) and why we divide the whole thing by 40?
Siva said:
9 years ago
@Chahat.
First, 15 overs team scored 120 runs at rate 6.2 and 183 runs need to be scored to reach 303 in 35 overs so req rate is 183/35 = 5.22.
First, 15 overs team scored 120 runs at rate 6.2 and 183 runs need to be scored to reach 303 in 35 overs so req rate is 183/35 = 5.22.
Siva said:
9 years ago
@Pranav.
Batsman scored 87 runs in his 17th innings as we all know that average is nothing but equal distribution.
So we can say that his increased average should be shared to every innings so 17*3=51 now we can clearly say that if he wants to increase his average he has to score more runs than the previous innings. so answer 87-17 * 3=> 87 - 51 = 36.
Batsman scored 87 runs in his 17th innings as we all know that average is nothing but equal distribution.
So we can say that his increased average should be shared to every innings so 17*3=51 now we can clearly say that if he wants to increase his average he has to score more runs than the previous innings. so answer 87-17 * 3=> 87 - 51 = 36.
Chahat sony said:
9 years ago
In the first 15 overs of a one-day cricket match, the run rate was only 6.2 to reach the target of 303 runs in the remaining 35 overs, the run rate should be?
Please solve it.
Please solve it.
Barun said:
9 years ago
Why is 3*10?
Rahul said:
9 years ago
x = req run rate.
(10 * 3.2) + (40 * x) = 282,
32 + 40x = 282,
40x = 250,
x = 6.25.
(10 * 3.2) + (40 * x) = 282,
32 + 40x = 282,
40x = 250,
x = 6.25.
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