Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
137 comments Page 4 of 14.
Jitender said:
1 decade ago
Ten over run rate is 3.2
So 10*3.2= 32.
Then Target 282-32 = 250.
Remaining over is 40.
250/40= 6.25 answer.
So 10*3.2= 32.
Then Target 282-32 = 250.
Remaining over is 40.
250/40= 6.25 answer.
(1)
Shobhita said:
1 decade ago
Why we are minus 282 - 32?
(1)
Manish said:
1 decade ago
I need basic method.
(1)
Vinod said:
2 decades ago
Why we are writing 3.2*10 ?
Dilepkumar said:
2 decades ago
They asking only remainig 40 over run rate. So why use of first 10 over?
Kavita said:
2 decades ago
How do we arrive at the solution.? What is the logic?
Pratik Mehta said:
2 decades ago
@Kavita : Run rate * overs = runs scored.
So now Run rate = Runs scored/required / overs.
There 282 - (3.2 x 10) = Runs required
Remaining overs are 40.
So now Run rate = Runs scored/required / overs.
There 282 - (3.2 x 10) = Runs required
Remaining overs are 40.
Ranjith said:
2 decades ago
Why do we minus 282-(3.2*10)...?
Muhundhan said:
2 decades ago
So we calculate the runs in the first 10 overs
first 10 overs they got 32 runs
remaining 40 overs they got 250
250 / 40 =6.25
first 10 overs they got 32 runs
remaining 40 overs they got 250
250 / 40 =6.25
Abc said:
2 decades ago
Thanks muhundhan thats great.
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