Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
137 comments Page 2 of 14.
Ahmed Raafat said:
3 years ago
Run rate = number of runs/number of overs.
(15)
Suchi said:
6 years ago
Use the Average formula :
Average = sum of observations/number of observations.
For first 10 overs :
3.2 = Sum/10 --> Sum = 32--> Run in first 10 overs.
The total score is 282. First 10 overs, we scored 32 runs. So, remaining (282-32) runs=250 runs in 40 overs.
Applying the formula:
Average = sum of observations/number of observations.
Average= 250/40 = 6.25.
Average = sum of observations/number of observations.
For first 10 overs :
3.2 = Sum/10 --> Sum = 32--> Run in first 10 overs.
The total score is 282. First 10 overs, we scored 32 runs. So, remaining (282-32) runs=250 runs in 40 overs.
Applying the formula:
Average = sum of observations/number of observations.
Average= 250/40 = 6.25.
(14)
Kondru Durga Srinu said:
2 years ago
So we calculate the runs in the first 10 overs = 10 * 3.2
First 10 overs they got 32 runs
Total runs for 50 overs is 282
Then, the remaining 40 overs they got = 282 - 32 = 250.
250/40 = 6.25
First 10 overs they got 32 runs
Total runs for 50 overs is 282
Then, the remaining 40 overs they got = 282 - 32 = 250.
250/40 = 6.25
(11)
Abhay Ranjan said:
2 months ago
Run rate = Total runs scored/total overs.
in the 10 overs;
3.2 = total run scores/10.
So, total run = 3.2 * 10 = 32.
The remaining runs we have to score in the 40 overs is (282-32 = 250).
Run rate = Total runs scored/total overs.
Run rate = 250/40 = 6.25.
in the 10 overs;
3.2 = total run scores/10.
So, total run = 3.2 * 10 = 32.
The remaining runs we have to score in the 40 overs is (282-32 = 250).
Run rate = Total runs scored/total overs.
Run rate = 250/40 = 6.25.
(10)
Masthan said:
6 years ago
10 * 3.2 = 32
40 * X = 282
=> 282 - 32 = 250.
40X = 250.
X = 250/40.
X = 6.25.
40 * X = 282
=> 282 - 32 = 250.
40X = 250.
X = 250/40.
X = 6.25.
(9)
Manalan said:
5 years ago
First 10 over,
3.2 = 10 * 3.2 = 32runs.
40 overs is 282 = 282-32.
= 250.
250 ÷ 40 = 6.25,
6.25.
3.2 = 10 * 3.2 = 32runs.
40 overs is 282 = 282-32.
= 250.
250 ÷ 40 = 6.25,
6.25.
(9)
Sonam chugh said:
2 months ago
It's very simple.
Target 282.
40 overs are remaining.
3.2 run rate * 10 over = 32 score till know.
282 - 32 = 250 need to win the game.
40x = 250,
=> x = 40/250,
Hence, the run rate is 6.25.
Target 282.
40 overs are remaining.
3.2 run rate * 10 over = 32 score till know.
282 - 32 = 250 need to win the game.
40x = 250,
=> x = 40/250,
Hence, the run rate is 6.25.
(8)
Balaji said:
5 years ago
First 10 overs run rate 3.2=3.2 * 10 = 32.
Next, 40 overs is 282 = 282 - 32 = 250.
250 ÷ 40 overs = 6.25.
So, the answer is 6.25.
Next, 40 overs is 282 = 282 - 32 = 250.
250 ÷ 40 overs = 6.25.
So, the answer is 6.25.
(6)
Cherry aishu said:
2 years ago
Avg of 6 months = (6435+6927+6855+7230+6562+x)/6 = 6500.
(34009+x)/6 = 6500,
34009+x = 39000,
x = 39000-34009,
x = 4991.
(34009+x)/6 = 6500,
34009+x = 39000,
x = 39000-34009,
x = 4991.
(6)
Shreya said:
6 years ago
In a cricket match, Ashwin scored 40perct. Of total run scored by his team & Arijit scored 140 run which is 200/9perct less than Ashwin's score, find total run scored by Ashwin's team, Anyone please answer it.
(3)
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