Aptitude - Average - Discussion

@All.
For simple understanding.

Total Runs at the end = 282 Runs
Run Rate of 1st 10 overs = 3.2
Total Runs score in 1st 10 overs = 10*3.2 = 32Runs.

The question is what should be the Run Rate of the next 40 overs to get 282 Runs at the end of innings?
Let the Run Rate of 40overs be x
Total runs scored in 40 overs = 40*x = 40x.
We know that Total runs= Runs in 1st 10overs+runs in next 40 overs
i.e : 282 = 32 + 40x.
282-32= 40x,
250 = 40x,
x = 250/40,
x = 6.25.

Hence And 6.25 Run Rate is the right answer.

For cross-checking

282 = 32 + (40*6.25),
282 = 32 + 250,
282 = 282.

Use the Average formula :

Average = sum of observations/number of observations.

For first 10 overs :
3.2 = Sum/10 --> Sum = 32--> Run in first 10 overs.
The total score is 282. First 10 overs, we scored 32 runs. So, remaining (282-32) runs=250 runs in 40 overs.

Applying the formula:

Average = sum of observations/number of observations.
Average= 250/40 = 6.25.

So we calculate the runs in the first 10 overs = 10 * 3.2
First 10 overs they got 32 runs
Total runs for 50 overs is 282
Then, the remaining 40 overs they got = 282 - 32 = 250.
250/40 = 6.25

10 * 3.2 = 32
40 * X = 282
=> 282 - 32 = 250.

40X = 250.
X = 250/40.
X = 6.25.

First 10 over,
3.2 = 10 * 3.2 = 32runs.
40 overs is 282 = 282-32.
= 250.

250 ÷ 40 = 6.25,
6.25.

First 10 overs run rate 3.2=3.2 * 10 = 32.
Next, 40 overs is 282 = 282 - 32 = 250.
250 ÷ 40 overs = 6.25.
So, the answer is 6.25.

Avg of 6 months = (6435+6927+6855+7230+6562+x)/6 = 6500.
(34009+x)/6 = 6500,
34009+x = 39000,
x = 39000-34009,
x = 4991.

In a cricket match, Ashwin scored 40perct. Of total run scored by his team & Arijit scored 140 run which is 200/9perct less than Ashwin's score, find total run scored by Ashwin's team, Anyone please answer it.

Iron manufacturing company produced a total of 3000 tons of iron in January of a particular year. Starting from February its production increased by 200 tons every month over the previous months until the end of that year. Find its average monthly production (in tons) for that year.

First 10 overs ----> 3.2 runrate.
Remaining 40 overs ----> x runrate.

(10*3.2)+(40*x) = 282,
32+40x = 282,
X = 25/4,
X = 6.25.