Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 2)
2.
Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:
Answer: Option
Explanation:
Since first and second varieties are mixed in equal proportions.
| So, their average price = Rs. |  |
126 + 135 |  |
= Rs. 130.50 |
| 2 |
So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x.
By the rule of alligation, we have:
| Cost of 1 kg of 1st kind Cost of 1 kg tea of 2nd kind | ||
| Rs. 130.50 | Mean Price Rs. 153 | Rs. x |
| (x - 153) | 22.50 | |
 |
x - 153 | = 1 |
| 22.50 |
x - 153 = 22.50
x = 175.50
Discussion:
62 comments Page 5 of 7.
Pratima said:
1 decade ago
How this mean price is calculated in allegation problems?Is there any particular way of calculating mean value?
Sanjeev sharma said:
1 decade ago
OK lets assume that we have 4 kg of mixed sugar so according to ratio provided we will have,
1 kg of 126/kg.
1 kg of 135/kg.
2 kg of x/kg.
We have sold.
4kgs of @153/kg so total = 4*153 = 612Rs.
126+135+2X = 612.
2X = 612-261.
2X = 351.
X = 175.50.
1 kg of 126/kg.
1 kg of 135/kg.
2 kg of x/kg.
We have sold.
4kgs of @153/kg so total = 4*153 = 612Rs.
126+135+2X = 612.
2X = 612-261.
2X = 351.
X = 175.50.
Maya said:
1 decade ago
Three mixtures are in the ratio 1:1:2 and prices given that 126, 135, P.
1*126+1*135+2*P = (1+1+2)153.
On solving, we get P = 175.5.
1*126+1*135+2*P = (1+1+2)153.
On solving, we get P = 175.5.
Amit said:
1 decade ago
We have ratio of 1:1:2.
So we will assume third as x and eq become,
126+135+2x=4*(153)//per kg that's why * 4 ie (1+1+2) as ratio says,
2x = 612-261.
x = 351/2.
x = 175.50.
So we will assume third as x and eq become,
126+135+2x=4*(153)//per kg that's why * 4 ie (1+1+2) as ratio says,
2x = 612-261.
x = 351/2.
x = 175.50.
YAW said:
1 decade ago
Why do you keep dividing it by 4?
Prakash said:
1 decade ago
126*1/4+135*1/4+x*2/4 = 153.
126+135+2x = 153*4.
261+2x = 612.
x = 175.5.
Hence you have to take per kg how much from total ratio that's what here 126*1/4.
126+135+2x = 153*4.
261+2x = 612.
x = 175.5.
Hence you have to take per kg how much from total ratio that's what here 126*1/4.
Tanmay said:
1 decade ago
@Ramakhanna.
Will you please explain your third step?
Will you please explain your third step?
Karthika said:
1 decade ago
1/4 means?
Md Salman said:
1 decade ago
The mixture contain the tea in the ratio of 1:1:2.
So if the mixture contain 1, 1 kg of type 1 and 2 the the weight of third type is 2 kg.
Now 126+135+2*x = 4*153.
261+2*x = 612.
2*x = 612-261.
2*x = 351.
x = 175.50.
So if the mixture contain 1, 1 kg of type 1 and 2 the the weight of third type is 2 kg.
Now 126+135+2*x = 4*153.
261+2*x = 612.
2*x = 612-261.
2*x = 351.
x = 175.50.
Malli Reddy said:
1 decade ago
Given the mixture contain in the ratio 1:1:2.
Then the quantities mixed are type1-x;type2-x;type3-2x.
Assume the price of third quantity is y.
Given average cost 153:
From weighted average formula (126x+135x+y2x)/4x = 153.
By solving y = 175.50.
Then the quantities mixed are type1-x;type2-x;type3-2x.
Assume the price of third quantity is y.
Given average cost 153:
From weighted average formula (126x+135x+y2x)/4x = 153.
By solving y = 175.50.
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