Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 2)
2.
Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:
Answer: Option
Explanation:
Since first and second varieties are mixed in equal proportions.
| So, their average price = Rs. |  |
126 + 135 |  |
= Rs. 130.50 |
| 2 |
So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x.
By the rule of alligation, we have:
| Cost of 1 kg of 1st kind Cost of 1 kg tea of 2nd kind | ||
| Rs. 130.50 | Mean Price Rs. 153 | Rs. x |
| (x - 153) | 22.50 | |
 |
x - 153 | = 1 |
| 22.50 |
x - 153 = 22.50
x = 175.50
Discussion:
62 comments Page 1 of 7.
Suren said:
2 decades ago
Totally there are 4kg mixture which costs 153.
therfore,(126+135+x)/4=153
x=351.
Here x is the price for 2Kg.
therefore x=175.50
therfore,(126+135+x)/4=153
x=351.
Here x is the price for 2Kg.
therefore x=175.50
Ragul said:
1 decade ago
Problem is simple.
(126+135+x) * (k+k+2K) =153* (k+K+2K).
When you solve above one, you will get x.
(126+135+x) * (k+k+2K) =153* (k+K+2K).
When you solve above one, you will get x.
Uma Upadhyay said:
1 decade ago
Say the unknown quantity is X.
Then (126*1+135*1+2*x)/(1+1+2)= 153
on solving X= 175.50
Then (126*1+135*1+2*x)/(1+1+2)= 153
on solving X= 175.50
Satish said:
1 decade ago
x - 153 = 1
------
22.50
will u explaim dis step,,,,,,,Plz,,,,
------
22.50
will u explaim dis step,,,,,,,Plz,,,,
Ramakhanna said:
1 decade ago
Let the three varieties be A,B,C.
the ratio is given as 1:1:2.
Let x be the price of third variety per kg.
A B C
the cost is: Rs.126/kg Rs.135/kg Rs.x/kg
the amount
(from ratio): (1/4)kg (1/4)kg (1/2)kg
(in kg.)
cost of three varieties per kg = cost of the mixture per kg
so,
(126*(1/4))+(135*(1/4))+(x*(1/2))=153
after making calculation, x=175.5
so, the price of third variety per kg will be Rs.175.5
the ratio is given as 1:1:2.
Let x be the price of third variety per kg.
A B C
the cost is: Rs.126/kg Rs.135/kg Rs.x/kg
the amount
(from ratio): (1/4)kg (1/4)kg (1/2)kg
(in kg.)
cost of three varieties per kg = cost of the mixture per kg
so,
(126*(1/4))+(135*(1/4))+(x*(1/2))=153
after making calculation, x=175.5
so, the price of third variety per kg will be Rs.175.5
(1)
Shweta jain said:
1 decade ago
Good explanation Ramakhanna.
Ashwini Sriram said:
1 decade ago
I agree with Suren. The problem is simpler than it is explained here.
It is just (126+135+2x)/4= 153.
Where x is the price per kg.
It is just (126+135+2x)/4= 153.
Where x is the price per kg.
Chacha said:
1 decade ago
Suren you rocked.
Ankan said:
1 decade ago
@Uma Upadhyay.
You are right and you maked its so easy. Thanks and also.
@Suren because you both are following similar process and right one.
You are right and you maked its so easy. Thanks and also.
@Suren because you both are following similar process and right one.
San said:
1 decade ago
Price of all mixture 126+135+(2*X)
Number of kgs 1+1+2
Therefore mixture price per kg=(price of all mix)/(number of kgs)=153/kg
Hence X=175.5/kg .
Number of kgs 1+1+2
Therefore mixture price per kg=(price of all mix)/(number of kgs)=153/kg
Hence X=175.5/kg .
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