Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 2)
2.
Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:
Answer: Option
Explanation:
Since first and second varieties are mixed in equal proportions.
| So, their average price = Rs. |  |
126 + 135 |  |
= Rs. 130.50 |
| 2 |
So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x.
By the rule of alligation, we have:
| Cost of 1 kg of 1st kind Cost of 1 kg tea of 2nd kind | ||
| Rs. 130.50 | Mean Price Rs. 153 | Rs. x |
| (x - 153) | 22.50 | |
 |
x - 153 | = 1 |
| 22.50 |
x - 153 = 22.50
x = 175.50
Discussion:
62 comments Page 1 of 7.
Harshith said:
1 year ago
Here, 153 * 4 - 126 - 135/2 = 175.50.
(12)
Satya said:
1 year ago
Let those 3 items be a,b,c.
Average of a,b, and 2c = 153.
Whereas a=126 and b=135.
So, here we have a conclusion that the 2c value is more than 157 but the question is how much?
And the answer is 153-135 = 18.
And 153-126=27.
2c gave 18+27=45 to a and c then those values become 153
If 2c gives 45 to a and b it still has its average value of 153
If 2c gives 45 then, c gives= 45/2 = 22.50.
If c never gives that 22.50 to a and b to make an average value then the value of c was = 153 + 22.50 = 175.50.
Average of a,b, and 2c = 153.
Whereas a=126 and b=135.
So, here we have a conclusion that the 2c value is more than 157 but the question is how much?
And the answer is 153-135 = 18.
And 153-126=27.
2c gave 18+27=45 to a and c then those values become 153
If 2c gives 45 to a and b it still has its average value of 153
If 2c gives 45 then, c gives= 45/2 = 22.50.
If c never gives that 22.50 to a and b to make an average value then the value of c was = 153 + 22.50 = 175.50.
(8)
Niharika said:
5 years ago
Third Verity = x
126 * 1 + 135 * 1 + X * 2/1 + 1 + 2 = 153.
X = 175.50.
126 * 1 + 135 * 1 + X * 2/1 + 1 + 2 = 153.
X = 175.50.
(73)
Rakesh said:
5 years ago
Total units(1:1:2)= 1+1+2=4 (4kgs).
Total sum =avg * no. of units =153 * 4 = 612.
Remove first two =612-126-135 = 351.
Hence as the third variety holds 2 units (i.e. 2kgs).
1kg price = 351/2 =175.5.
In short:
Price of third variety = (153* 4 - 126 - 135)/2 =175.5.
Total sum =avg * no. of units =153 * 4 = 612.
Remove first two =612-126-135 = 351.
Hence as the third variety holds 2 units (i.e. 2kgs).
1kg price = 351/2 =175.5.
In short:
Price of third variety = (153* 4 - 126 - 135)/2 =175.5.
(180)
Rashmitha said:
6 years ago
Have anyone got 164.25 as answer.
(11)
Rachana said:
6 years ago
@Boopathy.
As the ratio given is 1:1:2.
So, we apply alligation for this. By observing this 1 is repeated twice so take average of it . And you get the value of c=130.5 Rs and value of d=153Rs is given in alligations rule.
As the ratio given is 1:1:2.
So, we apply alligation for this. By observing this 1 is repeated twice so take average of it . And you get the value of c=130.5 Rs and value of d=153Rs is given in alligations rule.
(2)
Boopathy said:
6 years ago
I am not understanding. Please explain to me.
(7)
Gopeswar said:
7 years ago
The basic mixture and alligation formulae say:
Average =(N1A1+N2A2+....+NnAn)/(N1+N2+.....Nn)
Therefore: 153=(126*1+135*1+2*x)/(1+1+2).
solve and find x, here x is the price of the third variety of price.
Average =(N1A1+N2A2+....+NnAn)/(N1+N2+.....Nn)
Therefore: 153=(126*1+135*1+2*x)/(1+1+2).
solve and find x, here x is the price of the third variety of price.
(5)
Naveen said:
7 years ago
Simple formule:
(1:1:2)/4=153
(126+135+2X)/4 = 153,
261+2X = 4 * 153
261+2X = 612,
2X = 612-261,
2X = 351,
x = 175.5.
(1:1:2)/4=153
(126+135+2X)/4 = 153,
261+2X = 4 * 153
261+2X = 612,
2X = 612-261,
2X = 351,
x = 175.5.
(42)
Sathish said:
7 years ago
1 : 1 : 2.
So 126+135/2=130.5 third varity.
(1*126)+(1*126)+(2*130.5) = 612 total price.
612 - 126 - 135 = 351 third varity price.
351/2 = 175.5.
So 126+135/2=130.5 third varity.
(1*126)+(1*126)+(2*130.5) = 612 total price.
612 - 126 - 135 = 351 third varity price.
351/2 = 175.5.
(4)
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