### Discussion :: Alligation or Mixture - General Questions (Q.No.2)

Suren said: (Jul 29, 2010) | |

Totally there are 4kg mixture which costs 153. therfore,(126+135+x)/4=153 x=351. Here x is the price for 2Kg. therefore x=175.50 |

Ragul said: (Oct 12, 2010) | |

Problem is simple. (126+135+x) * (k+k+2K) =153* (k+K+2K). When you solve above one, you will get x. |

Uma Upadhyay said: (Oct 15, 2010) | |

Say the unknown quantity is X. Then (126*1+135*1+2*x)/(1+1+2)= 153 on solving X= 175.50 |

Satish said: (Nov 22, 2010) | |

x - 153 = 1 ------ 22.50 will u explaim dis step,,,,,,,Plz,,,, |

Ramakhanna said: (May 15, 2011) | |

Let the three varieties be A,B,C. the ratio is given as 1:1:2. Let x be the price of third variety per kg. A B C the cost is: Rs.126/kg Rs.135/kg Rs.x/kg the amount (from ratio): (1/4)kg (1/4)kg (1/2)kg (in kg.) cost of three varieties per kg = cost of the mixture per kg so, (126*(1/4))+(135*(1/4))+(x*(1/2))=153 after making calculation, x=175.5 so, the price of third variety per kg will be Rs.175.5 |

Shweta Jain said: (Jun 7, 2011) | |

Good explanation Ramakhanna. |

Ashwini Sriram said: (Jul 14, 2011) | |

I agree with Suren. The problem is simpler than it is explained here. It is just (126+135+2x)/4= 153. Where x is the price per kg. |

Chacha said: (Jul 28, 2011) | |

Suren you rocked. |

Ankan said: (Sep 2, 2011) | |

@Uma Upadhyay. You are right and you maked its so easy. Thanks and also. @Suren because you both are following similar process and right one. |

San said: (Sep 19, 2011) | |

Price of all mixture 126+135+(2*X) Number of kgs 1+1+2 Therefore mixture price per kg=(price of all mix)/(number of kgs)=153/kg Hence X=175.5/kg . |

Preethi said: (Sep 21, 2011) | |

@suren. In the question 1kg of the mixture is mentioned as Rs 153 na? how can you say 4kg costs 153. Please explain. |

Charan said: (Nov 4, 2011) | |

(126+135+2x)/4 = 153 x=175.5rs |

Pratima said: (Jan 17, 2012) | |

I'm impressed with Uma Upadhyay. Explained with simple method. |

Nikhil said: (Feb 14, 2012) | |

How come 175.5? |

Neelesh said: (May 5, 2012) | |

Thanks suren and uma both method much simple as explained here. |

Prince Sethi said: (May 21, 2012) | |

Simple answer here: Suppose there are three types of tea:type 1=126kg Type2=135kg Type3=xkg Now 1/4*126=31.5 Again 1/4*135=33.75 Now 2/4*x=x/2 Now addition 31.5+33.75+1/2x=153 x/2=153-65.25 x=175.50 Let me know in-case of any issues |

Lokesh Reddy said: (Jun 23, 2012) | |

126kg-1st 135kg-2nd xkg-3rd 1 : 1 : 2 (126*1 + 135*1 + 2*x )/ 4 = (153) total mixture. By solving, x=170.50. |

Pratima said: (Oct 31, 2012) | |

How this mean price is calculated in allegation problems?Is there any particular way of calculating mean value? |

Sanjeev Sharma said: (Jul 20, 2013) | |

OK lets assume that we have 4 kg of mixed sugar so according to ratio provided we will have, 1 kg of 126/kg. 1 kg of 135/kg. 2 kg of x/kg. We have sold. 4kgs of @153/kg so total = 4*153 = 612Rs. 126+135+2X = 612. 2X = 612-261. 2X = 351. X = 175.50. |

Maya said: (Dec 20, 2013) | |

Three mixtures are in the ratio 1:1:2 and prices given that 126, 135, P. 1*126+1*135+2*P = (1+1+2)153. On solving, we get P = 175.5. |

Amit said: (Jan 21, 2014) | |

We have ratio of 1:1:2. So we will assume third as x and eq become, 126+135+2x=4*(153)//per kg that's why * 4 ie (1+1+2) as ratio says, 2x = 612-261. x = 351/2. x = 175.50. |

Yaw said: (Jan 28, 2015) | |

Why do you keep dividing it by 4? |

Prakash said: (May 28, 2015) | |

126*1/4+135*1/4+x*2/4 = 153. 126+135+2x = 153*4. 261+2x = 612. x = 175.5. Hence you have to take per kg how much from total ratio that's what here 126*1/4. |

Tanmay said: (Jul 27, 2015) | |

@Ramakhanna. Will you please explain your third step? |

Karthika said: (Aug 11, 2015) | |

1/4 means? |

Md Salman said: (Aug 17, 2015) | |

The mixture contain the tea in the ratio of 1:1:2. So if the mixture contain 1, 1 kg of type 1 and 2 the the weight of third type is 2 kg. Now 126+135+2*x = 4*153. 261+2*x = 612. 2*x = 612-261. 2*x = 351. x = 175.50. |

Malli Reddy said: (Aug 29, 2015) | |

Given the mixture contain in the ratio 1:1:2. Then the quantities mixed are type1-x;type2-x;type3-2x. Assume the price of third quantity is y. Given average cost 153: From weighted average formula (126x+135x+y2x)/4x = 153. By solving y = 175.50. |

Anil Kishore said: (Nov 17, 2015) | |

Why in the explanation? (x-153)/22.50 = 1. |

Sameer Khan said: (Mar 5, 2016) | |

Guys it explained in a general way. |

Udit said: (Jun 9, 2016) | |

It also solve by; 153 - 130.5 = 22.5. |

Piyush said: (Jun 28, 2016) | |

What if the ratio was something different? how to solve through the same method. |

Adhitya said: (Jul 14, 2016) | |

(126 + 135 + 2x)/4 = 153, 2x = 35, x = 170.5. |

Parithi said: (Jul 20, 2016) | |

Can you explain clearly? |

Sucharitha said: (Aug 18, 2016) | |

Can you please explain, if suppose the costs of three varieties are given but ratios are not given. Then what will be the solution? |

Bikram said: (Sep 27, 2016) | |

Take the average of 126 & 135 = 130.50, Now deduct 130.50 from 153. => 153 - 130.50 = 22.50, Then add 22.50 with 153. => 153 + 22.50, Finally, the answer is 175.50 |

Tejas said: (Oct 7, 2016) | |

1 : 1 : 2 = 126 + 135 + 2x. 126 + 135 + 2x = 153 * 4. x = 175.50. |

Dinesh said: (Nov 17, 2016) | |

Short and simple explanation. Thanks @Suren. |

Jitender said: (Dec 6, 2016) | |

Simple: (1st quantity * its ratio + second quantity * it's ratio + third quantity * it's ratio)/sum of all ratios = Mean price. (126x1 + 135x1 + 2xY)/4 = 153, 2Y = 351 , Y = 175.5. |

Anu said: (Jan 2, 2017) | |

Please explain how to come 22.50? |

Manisha Panda said: (Mar 1, 2017) | |

@Ashwini. Your answer was short, precise and understandable. Thanks |

Nasir said: (Mar 17, 2017) | |

Let there is total x kg of tea and the price of third variety be Rs y per kg. => (126*1/4*x) + (135*1/4*x) + (y*1/2*x) = x * 153. On solving the above eqn, we get y = 175.5. |

Manish said: (Apr 2, 2017) | |

126 * 1 + 135 * 1 + x * 2 = 4 * 153, x = 175.5. |

Rajat Gupta said: (Apr 16, 2017) | |

153-126 = 27, 153-135 = 18, 27+18/2 = 22.5, 153+22.5 = 175.5 easily. |

Nidhi said: (Jun 15, 2017) | |

How 135? from where did it came. |

Mounika said: (Jul 21, 2017) | |

1 : 1 : 2 ratio. So, we can take it as 1/4kg 1/4kg and 1/2 kg. So, the answer ( 1/4)*126+(1/4)*135+(1/2)*x = 153. |

Ayesha Sultana said: (Aug 2, 2017) | |

Problem is simple (126*1 + 135*1 + 2x)/(1+1+2) = 153, 126+135+2x / 4 = 153, 261+2x= 153*4, 261+2x=612, 2x=612-261, 2x=351, X =351/2, X=175.5. |

Goutam_De said: (Nov 19, 2017) | |

(126 + 135 + 2x)/4 = 153, 2x = 612-261=351, x=351/2, x = 170.5. |

Suresh Arora said: (Dec 29, 2017) | |

I cannot understand. Anyone help me to get it. |

Priya said: (Jun 1, 2018) | |

By the diagram, we can choose right side after subtraction first. So it will be x-153 and then choose left after subtraction 22.5. Divide the values x-153/22. 5 we can get the answer. |

Tushar Agarwal said: (Jul 19, 2018) | |

126x + 135y + Xz/x + y+z = 153; consider this formula for ratios and we know x:y:z=1:1:2. So substituting x, y and z and calculating X we get X=175.50. |

Saidul said: (Aug 2, 2018) | |

X:Y:Z=1:1:2 (total=4). 153tk/kg (total amount=153*4=612tk), 1st two(135+126=261tk), 3rd=612-261=351tk, As 3rd variety was 2kg, then 1kh price is=315 ÷ 2=175.50tk (Ans.) |

Naveen Gaddam said: (Aug 23, 2018) | |

Give the ratio of three type of sugars are in =1:1:2. 1/4 kgs of the first two types and 2/4 kgs of third type sugar. assume third type sugar price=x per kg. (1/4)*126+(1/4)*135+ (2/4)*x=153. (126+135+2x)/4 = 153. 261+2x=612.. 2x=351. x=175.50. |

Sathish said: (Dec 6, 2018) | |

1 : 1 : 2. So 126+135/2=130.5 third varity. (1*126)+(1*126)+(2*130.5) = 612 total price. 612 - 126 - 135 = 351 third varity price. 351/2 = 175.5. |

Naveen said: (Jan 24, 2019) | |

Simple formule: (1:1:2)/4=153 (126+135+2X)/4 = 153, 261+2X = 4 * 153 261+2X = 612, 2X = 612-261, 2X = 351, x = 175.5. |

Gopeswar said: (Mar 13, 2019) | |

The basic mixture and alligation formulae say: Average =(N1A1+N2A2+....+NnAn)/(N1+N2+.....Nn) Therefore: 153=(126*1+135*1+2*x)/(1+1+2). solve and find x, here x is the price of the third variety of price. |

Boopathy said: (Jul 2, 2019) | |

I am not understanding. Please explain to me. |

Rachana said: (Jul 13, 2019) | |

@Boopathy. As the ratio given is 1:1:2. So, we apply alligation for this. By observing this 1 is repeated twice so take average of it . And you get the value of c=130.5 Rs and value of d=153Rs is given in alligations rule. |

Rashmitha said: (Oct 1, 2019) | |

Have anyone got 164.25 as answer. |

Rakesh said: (Aug 30, 2020) | |

Total units(1:1:2)= 1+1+2=4 (4kgs). Total sum =avg * no. of units =153 * 4 = 612. Remove first two =612-126-135 = 351. Hence as the third variety holds 2 units (i.e. 2kgs). 1kg price = 351/2 =175.5. In short: Price of third variety = (153* 4 - 126 - 135)/2 =175.5. |

Niharika said: (Nov 15, 2020) | |

Third Verity = x 126 * 1 + 135 * 1 + X * 2/1 + 1 + 2 = 153. X = 175.50. |

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