Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 2)
2.
Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:
Answer: Option
Explanation:
Since first and second varieties are mixed in equal proportions.
So, their average price = Rs. | ![]() |
126 + 135 | ![]() |
= Rs. 130.50 |
2 |
So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x.
By the rule of alligation, we have:
Cost of 1 kg of 1st kind Cost of 1 kg tea of 2nd kind | ||
Rs. 130.50 | Mean Price Rs. 153 | Rs. x |
(x - 153) | 22.50 |
![]() |
x - 153 | = 1 |
22.50 |
x - 153 = 22.50
x = 175.50
Discussion:
62 comments Page 2 of 7.
Naveen Gaddam said:
7 years ago
Give the ratio of three type of sugars are in =1:1:2.
1/4 kgs of the first two types and 2/4 kgs of third type sugar.
assume third type sugar price=x per kg.
(1/4)*126+(1/4)*135+ (2/4)*x=153.
(126+135+2x)/4 = 153.
261+2x=612..
2x=351.
x=175.50.
1/4 kgs of the first two types and 2/4 kgs of third type sugar.
assume third type sugar price=x per kg.
(1/4)*126+(1/4)*135+ (2/4)*x=153.
(126+135+2x)/4 = 153.
261+2x=612..
2x=351.
x=175.50.
(3)
Saidul said:
7 years ago
X:Y:Z=1:1:2 (total=4).
153tk/kg (total amount=153*4=612tk),
1st two(135+126=261tk),
3rd=612-261=351tk,
As 3rd variety was 2kg, then 1kh price is=315 ÷ 2=175.50tk (Ans.)
153tk/kg (total amount=153*4=612tk),
1st two(135+126=261tk),
3rd=612-261=351tk,
As 3rd variety was 2kg, then 1kh price is=315 ÷ 2=175.50tk (Ans.)
(2)
Tushar Agarwal said:
7 years ago
126x + 135y + Xz/x + y+z = 153;
consider this formula for ratios and we know x:y:z=1:1:2.
So substituting x, y and z and calculating X we get X=175.50.
consider this formula for ratios and we know x:y:z=1:1:2.
So substituting x, y and z and calculating X we get X=175.50.
Priya said:
7 years ago
By the diagram, we can choose right side after subtraction first. So it will be x-153 and then choose left after subtraction 22.5. Divide the values x-153/22. 5 we can get the answer.
Suresh arora said:
8 years ago
I cannot understand. Anyone help me to get it.
Goutam_De said:
8 years ago
(126 + 135 + 2x)/4 = 153,
2x = 612-261=351,
x=351/2,
x = 170.5.
2x = 612-261=351,
x=351/2,
x = 170.5.
(1)
Ayesha Sultana said:
8 years ago
Problem is simple
(126*1 + 135*1 + 2x)/(1+1+2) = 153,
126+135+2x / 4 = 153,
261+2x= 153*4,
261+2x=612,
2x=612-261,
2x=351,
X =351/2,
X=175.5.
(126*1 + 135*1 + 2x)/(1+1+2) = 153,
126+135+2x / 4 = 153,
261+2x= 153*4,
261+2x=612,
2x=612-261,
2x=351,
X =351/2,
X=175.5.
(1)
Mounika said:
8 years ago
1 : 1 : 2 ratio.
So, we can take it as 1/4kg 1/4kg and 1/2 kg.
So, the answer ( 1/4)*126+(1/4)*135+(1/2)*x = 153.
So, we can take it as 1/4kg 1/4kg and 1/2 kg.
So, the answer ( 1/4)*126+(1/4)*135+(1/2)*x = 153.
Nidhi said:
8 years ago
How 135? from where did it came.
RAJAT GUPTA said:
8 years ago
153-126 = 27,
153-135 = 18,
27+18/2 = 22.5,
153+22.5 = 175.5 easily.
153-135 = 18,
27+18/2 = 22.5,
153+22.5 = 175.5 easily.
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