Aptitude - Alligation or Mixture - Discussion

Discussion Forum : Alligation or Mixture - General Questions (Q.No. 2)
2.
Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:
Rs. 169.50
Rs. 170
Rs. 175.50
Rs. 180
Answer: Option
Explanation:

Since first and second varieties are mixed in equal proportions.

So, their average price = Rs. 126 + 135 = Rs. 130.50
2

So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x.

By the rule of alligation, we have:

Cost of 1 kg of 1st kind Cost of 1 kg tea of 2nd kind
Rs. 130.50 Mean Price
Rs. 153
Rs. x
(x - 153) 22.50

x - 153 = 1
22.50

x - 153 = 22.50

x = 175.50

Discussion:
65 comments Page 3 of 7.

Mounika said:   9 years ago
1 : 1 : 2 ratio.

So, we can take it as 1/4kg 1/4kg and 1/2 kg.
So, the answer ( 1/4)*126+(1/4)*135+(1/2)*x = 153.

Nidhi said:   9 years ago
How 135? from where did it came.

RAJAT GUPTA said:   9 years ago
153-126 = 27,
153-135 = 18,
27+18/2 = 22.5,
153+22.5 = 175.5 easily.

Manish said:   9 years ago
126 * 1 + 135 * 1 + x * 2 = 4 * 153,
x = 175.5.
(1)

Nasir said:   9 years ago
Let there is total x kg of tea and the price of third variety be Rs y per kg.

=> (126*1/4*x) + (135*1/4*x) + (y*1/2*x) = x * 153.
On solving the above eqn, we get y = 175.5.

Manisha panda said:   9 years ago
@Ashwini.

Your answer was short, precise and understandable. Thanks

Anu said:   9 years ago
Please explain how to come 22.50?

Jitender said:   9 years ago
Simple: (1st quantity * its ratio + second quantity * it's ratio + third quantity * it's ratio)/sum of all ratios = Mean price.

(126x1 + 135x1 + 2xY)/4 = 153,
2Y = 351 , Y = 175.5.

Dinesh said:   9 years ago
Short and simple explanation. Thanks @Suren.

Tejas said:   10 years ago
1 : 1 : 2 = 126 + 135 + 2x.
126 + 135 + 2x = 153 * 4.
x = 175.50.


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