Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 2)
2.
Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:
Answer: Option
Explanation:
Since first and second varieties are mixed in equal proportions.
| So, their average price = Rs. |  |
126 + 135 |  |
= Rs. 130.50 |
| 2 |
So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x.
By the rule of alligation, we have:
| Cost of 1 kg of 1st kind Cost of 1 kg tea of 2nd kind | ||
| Rs. 130.50 | Mean Price Rs. 153 | Rs. x |
| (x - 153) | 22.50 | |
 |
x - 153 | = 1 |
| 22.50 |
x - 153 = 22.50
x = 175.50
Discussion:
65 comments Page 4 of 7.
Bikram said:
10 years ago
Take the average of 126 & 135 = 130.50,
Now deduct 130.50 from 153.
=> 153 - 130.50 = 22.50,
Then add 22.50 with 153.
=> 153 + 22.50,
Finally, the answer is 175.50
Now deduct 130.50 from 153.
=> 153 - 130.50 = 22.50,
Then add 22.50 with 153.
=> 153 + 22.50,
Finally, the answer is 175.50
Sucharitha said:
10 years ago
Can you please explain, if suppose the costs of three varieties are given but ratios are not given.
Then what will be the solution?
Then what will be the solution?
Parithi said:
10 years ago
Can you explain clearly?
(1)
Adhitya said:
10 years ago
(126 + 135 + 2x)/4 = 153,
2x = 35,
x = 170.5.
2x = 35,
x = 170.5.
Piyush said:
10 years ago
What if the ratio was something different? how to solve through the same method.
Udit said:
10 years ago
It also solve by;
153 - 130.5 = 22.5.
153 - 130.5 = 22.5.
Sameer khan said:
1 decade ago
Guys it explained in a general way.
Anil kishore said:
1 decade ago
Why in the explanation?
(x-153)/22.50 = 1.
(x-153)/22.50 = 1.
Malli Reddy said:
1 decade ago
Given the mixture contain in the ratio 1:1:2.
Then the quantities mixed are type1-x;type2-x;type3-2x.
Assume the price of third quantity is y.
Given average cost 153:
From weighted average formula (126x+135x+y2x)/4x = 153.
By solving y = 175.50.
Then the quantities mixed are type1-x;type2-x;type3-2x.
Assume the price of third quantity is y.
Given average cost 153:
From weighted average formula (126x+135x+y2x)/4x = 153.
By solving y = 175.50.
Md Salman said:
1 decade ago
The mixture contain the tea in the ratio of 1:1:2.
So if the mixture contain 1, 1 kg of type 1 and 2 the the weight of third type is 2 kg.
Now 126+135+2*x = 4*153.
261+2*x = 612.
2*x = 612-261.
2*x = 351.
x = 175.50.
So if the mixture contain 1, 1 kg of type 1 and 2 the the weight of third type is 2 kg.
Now 126+135+2*x = 4*153.
261+2*x = 612.
2*x = 612-261.
2*x = 351.
x = 175.50.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers