Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 2)
2.
Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:
Answer: Option
Explanation:
Since first and second varieties are mixed in equal proportions.
So, their average price = Rs. | ![]() |
126 + 135 | ![]() |
= Rs. 130.50 |
2 |
So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x.
By the rule of alligation, we have:
Cost of 1 kg of 1st kind Cost of 1 kg tea of 2nd kind | ||
Rs. 130.50 | Mean Price Rs. 153 | Rs. x |
(x - 153) | 22.50 |
![]() |
x - 153 | = 1 |
22.50 |
x - 153 = 22.50
x = 175.50
Discussion:
62 comments Page 4 of 7.
Adhitya said:
9 years ago
(126 + 135 + 2x)/4 = 153,
2x = 35,
x = 170.5.
2x = 35,
x = 170.5.
Piyush said:
9 years ago
What if the ratio was something different? how to solve through the same method.
Udit said:
9 years ago
It also solve by;
153 - 130.5 = 22.5.
153 - 130.5 = 22.5.
Sameer khan said:
10 years ago
Guys it explained in a general way.
Anil kishore said:
10 years ago
Why in the explanation?
(x-153)/22.50 = 1.
(x-153)/22.50 = 1.
Malli Reddy said:
1 decade ago
Given the mixture contain in the ratio 1:1:2.
Then the quantities mixed are type1-x;type2-x;type3-2x.
Assume the price of third quantity is y.
Given average cost 153:
From weighted average formula (126x+135x+y2x)/4x = 153.
By solving y = 175.50.
Then the quantities mixed are type1-x;type2-x;type3-2x.
Assume the price of third quantity is y.
Given average cost 153:
From weighted average formula (126x+135x+y2x)/4x = 153.
By solving y = 175.50.
Md Salman said:
1 decade ago
The mixture contain the tea in the ratio of 1:1:2.
So if the mixture contain 1, 1 kg of type 1 and 2 the the weight of third type is 2 kg.
Now 126+135+2*x = 4*153.
261+2*x = 612.
2*x = 612-261.
2*x = 351.
x = 175.50.
So if the mixture contain 1, 1 kg of type 1 and 2 the the weight of third type is 2 kg.
Now 126+135+2*x = 4*153.
261+2*x = 612.
2*x = 612-261.
2*x = 351.
x = 175.50.
Karthika said:
1 decade ago
1/4 means?
Tanmay said:
1 decade ago
@Ramakhanna.
Will you please explain your third step?
Will you please explain your third step?
Prakash said:
1 decade ago
126*1/4+135*1/4+x*2/4 = 153.
126+135+2x = 153*4.
261+2x = 612.
x = 175.5.
Hence you have to take per kg how much from total ratio that's what here 126*1/4.
126+135+2x = 153*4.
261+2x = 612.
x = 175.5.
Hence you have to take per kg how much from total ratio that's what here 126*1/4.
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