Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 2)
2.
Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:
Answer: Option
Explanation:
Since first and second varieties are mixed in equal proportions.
| So, their average price = Rs. |  |
126 + 135 |  |
= Rs. 130.50 |
| 2 |
So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x.
By the rule of alligation, we have:
| Cost of 1 kg of 1st kind Cost of 1 kg tea of 2nd kind | ||
| Rs. 130.50 | Mean Price Rs. 153 | Rs. x |
| (x - 153) | 22.50 | |
 |
x - 153 | = 1 |
| 22.50 |
x - 153 = 22.50
x = 175.50
Discussion:
62 comments Page 5 of 7.
YAW said:
1 decade ago
Why do you keep dividing it by 4?
Amit said:
1 decade ago
We have ratio of 1:1:2.
So we will assume third as x and eq become,
126+135+2x=4*(153)//per kg that's why * 4 ie (1+1+2) as ratio says,
2x = 612-261.
x = 351/2.
x = 175.50.
So we will assume third as x and eq become,
126+135+2x=4*(153)//per kg that's why * 4 ie (1+1+2) as ratio says,
2x = 612-261.
x = 351/2.
x = 175.50.
Maya said:
1 decade ago
Three mixtures are in the ratio 1:1:2 and prices given that 126, 135, P.
1*126+1*135+2*P = (1+1+2)153.
On solving, we get P = 175.5.
1*126+1*135+2*P = (1+1+2)153.
On solving, we get P = 175.5.
Sanjeev sharma said:
1 decade ago
OK lets assume that we have 4 kg of mixed sugar so according to ratio provided we will have,
1 kg of 126/kg.
1 kg of 135/kg.
2 kg of x/kg.
We have sold.
4kgs of @153/kg so total = 4*153 = 612Rs.
126+135+2X = 612.
2X = 612-261.
2X = 351.
X = 175.50.
1 kg of 126/kg.
1 kg of 135/kg.
2 kg of x/kg.
We have sold.
4kgs of @153/kg so total = 4*153 = 612Rs.
126+135+2X = 612.
2X = 612-261.
2X = 351.
X = 175.50.
Pratima said:
1 decade ago
How this mean price is calculated in allegation problems?Is there any particular way of calculating mean value?
Lokesh reddy said:
1 decade ago
126kg-1st 135kg-2nd xkg-3rd
1 : 1 : 2
(126*1 + 135*1 + 2*x )/ 4 = (153) total mixture.
By solving,
x=170.50.
1 : 1 : 2
(126*1 + 135*1 + 2*x )/ 4 = (153) total mixture.
By solving,
x=170.50.
Prince Sethi said:
1 decade ago
Simple answer here:
Suppose there are three types of tea:type 1=126kg
Type2=135kg
Type3=xkg
Now
1/4*126=31.5
Again
1/4*135=33.75
Now
2/4*x=x/2
Now addition
31.5+33.75+1/2x=153
x/2=153-65.25
x=175.50
Let me know in-case of any issues
Suppose there are three types of tea:type 1=126kg
Type2=135kg
Type3=xkg
Now
1/4*126=31.5
Again
1/4*135=33.75
Now
2/4*x=x/2
Now addition
31.5+33.75+1/2x=153
x/2=153-65.25
x=175.50
Let me know in-case of any issues
Neelesh said:
1 decade ago
Thanks suren and uma both method much simple as explained here.
Nikhil said:
1 decade ago
How come 175.5?
Pratima said:
1 decade ago
I'm impressed with Uma Upadhyay. Explained with simple method.
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