Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 2)
2.
Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:
Answer: Option
Explanation:
Since first and second varieties are mixed in equal proportions.
| So, their average price = Rs. |  |
126 + 135 |  |
= Rs. 130.50 |
| 2 |
So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x.
By the rule of alligation, we have:
| Cost of 1 kg of 1st kind Cost of 1 kg tea of 2nd kind | ||
| Rs. 130.50 | Mean Price Rs. 153 | Rs. x |
| (x - 153) | 22.50 | |
 |
x - 153 | = 1 |
| 22.50 |
x - 153 = 22.50
x = 175.50
Discussion:
62 comments Page 6 of 7.
Charan said:
1 decade ago
(126+135+2x)/4 = 153
x=175.5rs
x=175.5rs
Preethi said:
1 decade ago
@suren.
In the question 1kg of the mixture is mentioned as Rs 153 na? how can you say 4kg costs 153.
Please explain.
In the question 1kg of the mixture is mentioned as Rs 153 na? how can you say 4kg costs 153.
Please explain.
San said:
1 decade ago
Price of all mixture 126+135+(2*X)
Number of kgs 1+1+2
Therefore mixture price per kg=(price of all mix)/(number of kgs)=153/kg
Hence X=175.5/kg .
Number of kgs 1+1+2
Therefore mixture price per kg=(price of all mix)/(number of kgs)=153/kg
Hence X=175.5/kg .
Ankan said:
1 decade ago
@Uma Upadhyay.
You are right and you maked its so easy. Thanks and also.
@Suren because you both are following similar process and right one.
You are right and you maked its so easy. Thanks and also.
@Suren because you both are following similar process and right one.
Chacha said:
1 decade ago
Suren you rocked.
Ashwini Sriram said:
1 decade ago
I agree with Suren. The problem is simpler than it is explained here.
It is just (126+135+2x)/4= 153.
Where x is the price per kg.
It is just (126+135+2x)/4= 153.
Where x is the price per kg.
Shweta jain said:
1 decade ago
Good explanation Ramakhanna.
Ramakhanna said:
1 decade ago
Let the three varieties be A,B,C.
the ratio is given as 1:1:2.
Let x be the price of third variety per kg.
A B C
the cost is: Rs.126/kg Rs.135/kg Rs.x/kg
the amount
(from ratio): (1/4)kg (1/4)kg (1/2)kg
(in kg.)
cost of three varieties per kg = cost of the mixture per kg
so,
(126*(1/4))+(135*(1/4))+(x*(1/2))=153
after making calculation, x=175.5
so, the price of third variety per kg will be Rs.175.5
the ratio is given as 1:1:2.
Let x be the price of third variety per kg.
A B C
the cost is: Rs.126/kg Rs.135/kg Rs.x/kg
the amount
(from ratio): (1/4)kg (1/4)kg (1/2)kg
(in kg.)
cost of three varieties per kg = cost of the mixture per kg
so,
(126*(1/4))+(135*(1/4))+(x*(1/2))=153
after making calculation, x=175.5
so, the price of third variety per kg will be Rs.175.5
(1)
Satish said:
1 decade ago
x - 153 = 1
------
22.50
will u explaim dis step,,,,,,,Plz,,,,
------
22.50
will u explaim dis step,,,,,,,Plz,,,,
Uma Upadhyay said:
1 decade ago
Say the unknown quantity is X.
Then (126*1+135*1+2*x)/(1+1+2)= 153
on solving X= 175.50
Then (126*1+135*1+2*x)/(1+1+2)= 153
on solving X= 175.50
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