Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 2)
2.
Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:
Answer: Option
Explanation:
Since first and second varieties are mixed in equal proportions.
| So, their average price = Rs. |  |
126 + 135 |  |
= Rs. 130.50 |
| 2 |
So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x.
By the rule of alligation, we have:
| Cost of 1 kg of 1st kind Cost of 1 kg tea of 2nd kind | ||
| Rs. 130.50 | Mean Price Rs. 153 | Rs. x |
| (x - 153) | 22.50 | |
 |
x - 153 | = 1 |
| 22.50 |
x - 153 = 22.50
x = 175.50
Discussion:
62 comments Page 2 of 7.
Preethi said:
1 decade ago
@suren.
In the question 1kg of the mixture is mentioned as Rs 153 na? how can you say 4kg costs 153.
Please explain.
In the question 1kg of the mixture is mentioned as Rs 153 na? how can you say 4kg costs 153.
Please explain.
Charan said:
1 decade ago
(126+135+2x)/4 = 153
x=175.5rs
x=175.5rs
Pratima said:
1 decade ago
I'm impressed with Uma Upadhyay. Explained with simple method.
Nikhil said:
1 decade ago
How come 175.5?
Neelesh said:
1 decade ago
Thanks suren and uma both method much simple as explained here.
Prince Sethi said:
1 decade ago
Simple answer here:
Suppose there are three types of tea:type 1=126kg
Type2=135kg
Type3=xkg
Now
1/4*126=31.5
Again
1/4*135=33.75
Now
2/4*x=x/2
Now addition
31.5+33.75+1/2x=153
x/2=153-65.25
x=175.50
Let me know in-case of any issues
Suppose there are three types of tea:type 1=126kg
Type2=135kg
Type3=xkg
Now
1/4*126=31.5
Again
1/4*135=33.75
Now
2/4*x=x/2
Now addition
31.5+33.75+1/2x=153
x/2=153-65.25
x=175.50
Let me know in-case of any issues
Lokesh reddy said:
1 decade ago
126kg-1st 135kg-2nd xkg-3rd
1 : 1 : 2
(126*1 + 135*1 + 2*x )/ 4 = (153) total mixture.
By solving,
x=170.50.
1 : 1 : 2
(126*1 + 135*1 + 2*x )/ 4 = (153) total mixture.
By solving,
x=170.50.
Pratima said:
1 decade ago
How this mean price is calculated in allegation problems?Is there any particular way of calculating mean value?
Sanjeev sharma said:
1 decade ago
OK lets assume that we have 4 kg of mixed sugar so according to ratio provided we will have,
1 kg of 126/kg.
1 kg of 135/kg.
2 kg of x/kg.
We have sold.
4kgs of @153/kg so total = 4*153 = 612Rs.
126+135+2X = 612.
2X = 612-261.
2X = 351.
X = 175.50.
1 kg of 126/kg.
1 kg of 135/kg.
2 kg of x/kg.
We have sold.
4kgs of @153/kg so total = 4*153 = 612Rs.
126+135+2X = 612.
2X = 612-261.
2X = 351.
X = 175.50.
Maya said:
1 decade ago
Three mixtures are in the ratio 1:1:2 and prices given that 126, 135, P.
1*126+1*135+2*P = (1+1+2)153.
On solving, we get P = 175.5.
1*126+1*135+2*P = (1+1+2)153.
On solving, we get P = 175.5.
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