Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 2)
2.
Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:
Answer: Option
Explanation:
Since first and second varieties are mixed in equal proportions.
| So, their average price = Rs. |  |
126 + 135 |  |
= Rs. 130.50 |
| 2 |
So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x.
By the rule of alligation, we have:
| Cost of 1 kg of 1st kind Cost of 1 kg tea of 2nd kind | ||
| Rs. 130.50 | Mean Price Rs. 153 | Rs. x |
| (x - 153) | 22.50 | |
 |
x - 153 | = 1 |
| 22.50 |
x - 153 = 22.50
x = 175.50
Discussion:
65 comments Page 4 of 7.
Suresh arora said:
8 years ago
I cannot understand. Anyone help me to get it.
Priya said:
8 years ago
By the diagram, we can choose right side after subtraction first. So it will be x-153 and then choose left after subtraction 22.5. Divide the values x-153/22. 5 we can get the answer.
Adhitya said:
10 years ago
(126 + 135 + 2x)/4 = 153,
2x = 35,
x = 170.5.
2x = 35,
x = 170.5.
Sakthivelmurugan S said:
6 days ago
Tea varieties 3.
1st - 126 per kg.
2nd - 135 per kg.
3 varieties found, but this ratio.
1 : 1 : 2.
1 ratio (126).
1 ratio (135).
2 ratio (x) but mixture 153 per kg.
126 + 135/2 = 130.5.
130.5 : 153 : x.
(x-153) : 153 - 130.5 = 22.5.
x - 153/22.50 = 1 (why I use it 1 because the ratio was 1:1).
x-153 = 22.50,
x = 153 + 22.50,
x = 175.50.
1st - 126 per kg.
2nd - 135 per kg.
3 varieties found, but this ratio.
1 : 1 : 2.
1 ratio (126).
1 ratio (135).
2 ratio (x) but mixture 153 per kg.
126 + 135/2 = 130.5.
130.5 : 153 : x.
(x-153) : 153 - 130.5 = 22.5.
x - 153/22.50 = 1 (why I use it 1 because the ratio was 1:1).
x-153 = 22.50,
x = 153 + 22.50,
x = 175.50.
Pratima said:
1 decade ago
How this mean price is calculated in allegation problems?Is there any particular way of calculating mean value?
Ragul said:
2 decades ago
Problem is simple.
(126+135+x) * (k+k+2K) =153* (k+K+2K).
When you solve above one, you will get x.
(126+135+x) * (k+k+2K) =153* (k+K+2K).
When you solve above one, you will get x.
Uma Upadhyay said:
2 decades ago
Say the unknown quantity is X.
Then (126*1+135*1+2*x)/(1+1+2)= 153
on solving X= 175.50
Then (126*1+135*1+2*x)/(1+1+2)= 153
on solving X= 175.50
Satish said:
2 decades ago
x - 153 = 1
------
22.50
will u explaim dis step,,,,,,,Plz,,,,
------
22.50
will u explaim dis step,,,,,,,Plz,,,,
Shweta jain said:
1 decade ago
Good explanation Ramakhanna.
Ashwini Sriram said:
1 decade ago
I agree with Suren. The problem is simpler than it is explained here.
It is just (126+135+2x)/4= 153.
Where x is the price per kg.
It is just (126+135+2x)/4= 153.
Where x is the price per kg.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers