Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 2)
2.
Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:
Answer: Option
Explanation:
Since first and second varieties are mixed in equal proportions.
| So, their average price = Rs. | ![]() |
126 + 135 | ![]() |
= Rs. 130.50 |
| 2 |
So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x.
By the rule of alligation, we have:
| Cost of 1 kg of 1st kind Cost of 1 kg tea of 2nd kind | ||
| Rs. 130.50 | Mean Price Rs. 153 | Rs. x |
| (x - 153) | 22.50 | |
|
x - 153 | = 1 |
| 22.50 |
x - 153 = 22.50
x = 175.50
Discussion:
65 comments Page 3 of 7.
Dinesh said:
9 years ago
Short and simple explanation. Thanks @Suren.
Bikram said:
10 years ago
Take the average of 126 & 135 = 130.50,
Now deduct 130.50 from 153.
=> 153 - 130.50 = 22.50,
Then add 22.50 with 153.
=> 153 + 22.50,
Finally, the answer is 175.50
Now deduct 130.50 from 153.
=> 153 - 130.50 = 22.50,
Then add 22.50 with 153.
=> 153 + 22.50,
Finally, the answer is 175.50
Jitender said:
9 years ago
Simple: (1st quantity * its ratio + second quantity * it's ratio + third quantity * it's ratio)/sum of all ratios = Mean price.
(126x1 + 135x1 + 2xY)/4 = 153,
2Y = 351 , Y = 175.5.
(126x1 + 135x1 + 2xY)/4 = 153,
2Y = 351 , Y = 175.5.
Anu said:
9 years ago
Please explain how to come 22.50?
Manisha panda said:
9 years ago
@Ashwini.
Your answer was short, precise and understandable. Thanks
Your answer was short, precise and understandable. Thanks
Tushar Agarwal said:
8 years ago
126x + 135y + Xz/x + y+z = 153;
consider this formula for ratios and we know x:y:z=1:1:2.
So substituting x, y and z and calculating X we get X=175.50.
consider this formula for ratios and we know x:y:z=1:1:2.
So substituting x, y and z and calculating X we get X=175.50.
Nasir said:
9 years ago
Let there is total x kg of tea and the price of third variety be Rs y per kg.
=> (126*1/4*x) + (135*1/4*x) + (y*1/2*x) = x * 153.
On solving the above eqn, we get y = 175.5.
=> (126*1/4*x) + (135*1/4*x) + (y*1/2*x) = x * 153.
On solving the above eqn, we get y = 175.5.
RAJAT GUPTA said:
9 years ago
153-126 = 27,
153-135 = 18,
27+18/2 = 22.5,
153+22.5 = 175.5 easily.
153-135 = 18,
27+18/2 = 22.5,
153+22.5 = 175.5 easily.
Nidhi said:
9 years ago
How 135? from where did it came.
Mounika said:
9 years ago
1 : 1 : 2 ratio.
So, we can take it as 1/4kg 1/4kg and 1/2 kg.
So, the answer ( 1/4)*126+(1/4)*135+(1/2)*x = 153.
So, we can take it as 1/4kg 1/4kg and 1/2 kg.
So, the answer ( 1/4)*126+(1/4)*135+(1/2)*x = 153.
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