Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 2)
2.
Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:
Answer: Option
Explanation:
Since first and second varieties are mixed in equal proportions.
| So, their average price = Rs. |  |
126 + 135 |  |
= Rs. 130.50 |
| 2 |
So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x.
By the rule of alligation, we have:
| Cost of 1 kg of 1st kind Cost of 1 kg tea of 2nd kind | ||
| Rs. 130.50 | Mean Price Rs. 153 | Rs. x |
| (x - 153) | 22.50 | |
 |
x - 153 | = 1 |
| 22.50 |
x - 153 = 22.50
x = 175.50
Discussion:
62 comments Page 2 of 7.
Rachana said:
6 years ago
@Boopathy.
As the ratio given is 1:1:2.
So, we apply alligation for this. By observing this 1 is repeated twice so take average of it . And you get the value of c=130.5 Rs and value of d=153Rs is given in alligations rule.
As the ratio given is 1:1:2.
So, we apply alligation for this. By observing this 1 is repeated twice so take average of it . And you get the value of c=130.5 Rs and value of d=153Rs is given in alligations rule.
(2)
Saidul said:
7 years ago
X:Y:Z=1:1:2 (total=4).
153tk/kg (total amount=153*4=612tk),
1st two(135+126=261tk),
3rd=612-261=351tk,
As 3rd variety was 2kg, then 1kh price is=315 ÷ 2=175.50tk (Ans.)
153tk/kg (total amount=153*4=612tk),
1st two(135+126=261tk),
3rd=612-261=351tk,
As 3rd variety was 2kg, then 1kh price is=315 ÷ 2=175.50tk (Ans.)
(2)
Parithi said:
9 years ago
Can you explain clearly?
(1)
Goutam_De said:
8 years ago
(126 + 135 + 2x)/4 = 153,
2x = 612-261=351,
x=351/2,
x = 170.5.
2x = 612-261=351,
x=351/2,
x = 170.5.
(1)
Ayesha Sultana said:
8 years ago
Problem is simple
(126*1 + 135*1 + 2x)/(1+1+2) = 153,
126+135+2x / 4 = 153,
261+2x= 153*4,
261+2x=612,
2x=612-261,
2x=351,
X =351/2,
X=175.5.
(126*1 + 135*1 + 2x)/(1+1+2) = 153,
126+135+2x / 4 = 153,
261+2x= 153*4,
261+2x=612,
2x=612-261,
2x=351,
X =351/2,
X=175.5.
(1)
Manish said:
8 years ago
126 * 1 + 135 * 1 + x * 2 = 4 * 153,
x = 175.5.
x = 175.5.
(1)
Ramakhanna said:
1 decade ago
Let the three varieties be A,B,C.
the ratio is given as 1:1:2.
Let x be the price of third variety per kg.
A B C
the cost is: Rs.126/kg Rs.135/kg Rs.x/kg
the amount
(from ratio): (1/4)kg (1/4)kg (1/2)kg
(in kg.)
cost of three varieties per kg = cost of the mixture per kg
so,
(126*(1/4))+(135*(1/4))+(x*(1/2))=153
after making calculation, x=175.5
so, the price of third variety per kg will be Rs.175.5
the ratio is given as 1:1:2.
Let x be the price of third variety per kg.
A B C
the cost is: Rs.126/kg Rs.135/kg Rs.x/kg
the amount
(from ratio): (1/4)kg (1/4)kg (1/2)kg
(in kg.)
cost of three varieties per kg = cost of the mixture per kg
so,
(126*(1/4))+(135*(1/4))+(x*(1/2))=153
after making calculation, x=175.5
so, the price of third variety per kg will be Rs.175.5
(1)
Charan said:
1 decade ago
(126+135+2x)/4 = 153
x=175.5rs
x=175.5rs
Nasir said:
9 years ago
Let there is total x kg of tea and the price of third variety be Rs y per kg.
=> (126*1/4*x) + (135*1/4*x) + (y*1/2*x) = x * 153.
On solving the above eqn, we get y = 175.5.
=> (126*1/4*x) + (135*1/4*x) + (y*1/2*x) = x * 153.
On solving the above eqn, we get y = 175.5.
Prince Sethi said:
1 decade ago
Simple answer here:
Suppose there are three types of tea:type 1=126kg
Type2=135kg
Type3=xkg
Now
1/4*126=31.5
Again
1/4*135=33.75
Now
2/4*x=x/2
Now addition
31.5+33.75+1/2x=153
x/2=153-65.25
x=175.50
Let me know in-case of any issues
Suppose there are three types of tea:type 1=126kg
Type2=135kg
Type3=xkg
Now
1/4*126=31.5
Again
1/4*135=33.75
Now
2/4*x=x/2
Now addition
31.5+33.75+1/2x=153
x/2=153-65.25
x=175.50
Let me know in-case of any issues
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