Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 2)
2.
Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:
Answer: Option
Explanation:
Since first and second varieties are mixed in equal proportions.
| So, their average price = Rs. |  |
126 + 135 |  |
= Rs. 130.50 |
| 2 |
So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x.
By the rule of alligation, we have:
| Cost of 1 kg of 1st kind Cost of 1 kg tea of 2nd kind | ||
| Rs. 130.50 | Mean Price Rs. 153 | Rs. x |
| (x - 153) | 22.50 | |
 |
x - 153 | = 1 |
| 22.50 |
x - 153 = 22.50
x = 175.50
Discussion:
65 comments Page 6 of 7.
Sucharitha said:
10 years ago
Can you please explain, if suppose the costs of three varieties are given but ratios are not given.
Then what will be the solution?
Then what will be the solution?
Sanjeev sharma said:
1 decade ago
OK lets assume that we have 4 kg of mixed sugar so according to ratio provided we will have,
1 kg of 126/kg.
1 kg of 135/kg.
2 kg of x/kg.
We have sold.
4kgs of @153/kg so total = 4*153 = 612Rs.
126+135+2X = 612.
2X = 612-261.
2X = 351.
X = 175.50.
1 kg of 126/kg.
1 kg of 135/kg.
2 kg of x/kg.
We have sold.
4kgs of @153/kg so total = 4*153 = 612Rs.
126+135+2X = 612.
2X = 612-261.
2X = 351.
X = 175.50.
Maya said:
1 decade ago
Three mixtures are in the ratio 1:1:2 and prices given that 126, 135, P.
1*126+1*135+2*P = (1+1+2)153.
On solving, we get P = 175.5.
1*126+1*135+2*P = (1+1+2)153.
On solving, we get P = 175.5.
Amit said:
1 decade ago
We have ratio of 1:1:2.
So we will assume third as x and eq become,
126+135+2x=4*(153)//per kg that's why * 4 ie (1+1+2) as ratio says,
2x = 612-261.
x = 351/2.
x = 175.50.
So we will assume third as x and eq become,
126+135+2x=4*(153)//per kg that's why * 4 ie (1+1+2) as ratio says,
2x = 612-261.
x = 351/2.
x = 175.50.
YAW said:
1 decade ago
Why do you keep dividing it by 4?
Prakash said:
1 decade ago
126*1/4+135*1/4+x*2/4 = 153.
126+135+2x = 153*4.
261+2x = 612.
x = 175.5.
Hence you have to take per kg how much from total ratio that's what here 126*1/4.
126+135+2x = 153*4.
261+2x = 612.
x = 175.5.
Hence you have to take per kg how much from total ratio that's what here 126*1/4.
Tanmay said:
1 decade ago
@Ramakhanna.
Will you please explain your third step?
Will you please explain your third step?
Karthika said:
1 decade ago
1/4 means?
Md Salman said:
1 decade ago
The mixture contain the tea in the ratio of 1:1:2.
So if the mixture contain 1, 1 kg of type 1 and 2 the the weight of third type is 2 kg.
Now 126+135+2*x = 4*153.
261+2*x = 612.
2*x = 612-261.
2*x = 351.
x = 175.50.
So if the mixture contain 1, 1 kg of type 1 and 2 the the weight of third type is 2 kg.
Now 126+135+2*x = 4*153.
261+2*x = 612.
2*x = 612-261.
2*x = 351.
x = 175.50.
Malli Reddy said:
1 decade ago
Given the mixture contain in the ratio 1:1:2.
Then the quantities mixed are type1-x;type2-x;type3-2x.
Assume the price of third quantity is y.
Given average cost 153:
From weighted average formula (126x+135x+y2x)/4x = 153.
By solving y = 175.50.
Then the quantities mixed are type1-x;type2-x;type3-2x.
Assume the price of third quantity is y.
Given average cost 153:
From weighted average formula (126x+135x+y2x)/4x = 153.
By solving y = 175.50.
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