Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 9)
9.
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
Answer: Option
Explanation:
Relative speed = (60+ 90) km/hr
| = |  |
150 x | 5 |  m/sec |
| 18 |
| = | |
125 | m/sec. |
| 3 |
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
| Required time = | |
2000 x | 3 | sec = 48 sec. |
| 125 |
Discussion:
111 comments Page 1 of 12.
Mosepher said:
3 weeks ago
@RAVI.
The time taken is still 48 seconds.
When two moving objects completely cross each other, the physics of relative motion dictates that the event is symmetrical.
Therefore, whether looking at the slower train crossing the faster one or the faster train crossing the slower one, the elapsed time is identical.
The time taken is still 48 seconds.
When two moving objects completely cross each other, the physics of relative motion dictates that the event is symmetrical.
Therefore, whether looking at the slower train crossing the faster one or the faster train crossing the slower one, the elapsed time is identical.
Jay Panchal said:
3 months ago
S = 90+60 = 150km/h.
D = 1.10+0.9 km = 2.0 km.
T = D/S.
So, T = (2/150) * 3600(to convert into sec).
D = 1.10+0.9 km = 2.0 km.
T = D/S.
So, T = (2/150) * 3600(to convert into sec).
(1)
DHANASURIYA M G said:
5 months ago
The time taken by the slower train to cross the faster train is 48 seconds.
Ravi said:
12 months ago
Then how can I get a faster train speed? Please, explain to me.
(3)
Subhash said:
1 year ago
T = D/S.
D = 1100m + 900m = 2,000.
S(relative) = (60+90) * 5/18 = 41.667,
T = 2000/41.667 =48.
D = 1100m + 900m = 2,000.
S(relative) = (60+90) * 5/18 = 41.667,
T = 2000/41.667 =48.
(3)
Nanda said:
1 year ago
Please explain the answer.
(1)
God Here said:
2 years ago
@All.
Here's the solution:
Total distance = 2km;
total speed = 150;
time in seconds = (2/150)x3600 = 48 Answer.
Here's the solution:
Total distance = 2km;
total speed = 150;
time in seconds = (2/150)x3600 = 48 Answer.
(14)
Tanmoy Pramanick said:
3 years ago
The right answer will be 28.8 sec.
(7)
Kaviprema said:
4 years ago
Soluution,
First, the direction of the train is opposite so we will add the speed s1+s2..
Then, the length of the train first and second train t1+t2..
S1 + S2=60 + 90 = 150 km/hr.
T1+T2 = 1.10 + 0.9 = 2 km.
Formula,
t= d/s
t = 2km/150km/hr
1km-1000m
So, 2km - 2000m.
t = 2000m/150 *5/18 m/sec.
Convert km/hr into m/sec;
(150 km/hr -> 5/18 m/sec).
After solving we will get,
t= 48sec.
First, the direction of the train is opposite so we will add the speed s1+s2..
Then, the length of the train first and second train t1+t2..
S1 + S2=60 + 90 = 150 km/hr.
T1+T2 = 1.10 + 0.9 = 2 km.
Formula,
t= d/s
t = 2km/150km/hr
1km-1000m
So, 2km - 2000m.
t = 2000m/150 *5/18 m/sec.
Convert km/hr into m/sec;
(150 km/hr -> 5/18 m/sec).
After solving we will get,
t= 48sec.
(19)
Shri said:
4 years ago
Yes, absolutely right Agree with you @Hadiyal Jignesh.
(3)
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