"Everything should be made as simple as possible, but not simpler."
- Albert Einstein
3.
A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?
[A].
Rs. 4991
[B].
Rs. 5991
[C].
Rs. 6001
[D].
Rs. 6991
Answer: Option D
Explanation:
Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Assume a nearest number in given number as average
Suppose 6500 as average
and then write down all as follows
6435+65=6500
6927-427=6500
6855-355=6500
7230-730=6500
6562-62=6500
the last number as y+x=6500
the effective should be zero if 6500 is correct average
+65-427-355-730-62+x=0
x=799
to get effective zero we should have the number is -799
therefore the required number is as follows...
4991(6500-799).
explanation is long but it is less time taken...
Aparna said:
(Sun, Jan 30, 2011 11:08:18 AM)
Ya you are exact avinash.
Even all t prblms should be solved by this method.
By considering t nearby value.
Abdus Samadh said:
(Fri, Feb 4, 2011 05:51:29 AM)
Mr. Avinash are you sure 6500-799=4991.
Mariya said:
(Tue, Feb 15, 2011 01:41:17 AM)
Avg=(6435+6927+6855+7230+6565+x)/6=6500
=(34012+x)=6*6500
x=39000-34012=4988 from this can select nearest ans...
Gautam Sharma said:
(Wed, Feb 16, 2011 06:42:18 AM)
At First, Multiply 6500x6=39000 (bcoz avg is asking in Q)
Then, add all the 5 sale i.e 34009,
Deduct 39000 from the total sale i.e.34009, it becomes 4991.
Required sale = Rs. [ (6500 x 6) - 34009 ]