# Aptitude - Average - Discussion

Discussion Forum : Average - General Questions (Q.No. 3)

3.

A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?

Answer: Option

Explanation:

Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.

Required sale = Rs. [ (6500 x 6) - 34009 ]

= Rs. (39000 - 34009)

= Rs. 4991.

Video Explanation: https://youtu.be/tP4hszReksU

Discussion:

59 comments Page 1 of 6.
Sriram said:
1 decade ago

Please give a short cut for this.

Nowshad said:
1 decade ago

Please give a simple solution for this.

Avinash said:
1 decade ago

Easy method for this is

Assume a nearest number in given number as average

Suppose 6500 as average

and then write down all as follows

6435+65=6500

6927-427=6500

6855-355=6500

7230-730=6500

6562-62=6500

the last number as y+x=6500

the effective should be zero if 6500 is correct average

+65-427-355-730-62+x=0

x=799

to get effective zero we should have the number is -799

therefore the required number is as follows...

4991(6500-799).

explanation is long but it is less time taken...

Assume a nearest number in given number as average

Suppose 6500 as average

and then write down all as follows

6435+65=6500

6927-427=6500

6855-355=6500

7230-730=6500

6562-62=6500

the last number as y+x=6500

the effective should be zero if 6500 is correct average

+65-427-355-730-62+x=0

x=799

to get effective zero we should have the number is -799

therefore the required number is as follows...

4991(6500-799).

explanation is long but it is less time taken...

Aparna said:
1 decade ago

Ya you are exact avinash.

Even all t prblms should be solved by this method.

By considering t nearby value.

Even all t prblms should be solved by this method.

By considering t nearby value.

Abdus samadh said:
1 decade ago

Mr. Avinash are you sure 6500-799=4991.

Mariya said:
1 decade ago

Avg=(6435+6927+6855+7230+6565+x)/6=6500

=(34012+x)=6*6500

x=39000-34012=4988 from this can select nearest ans...

=(34012+x)=6*6500

x=39000-34012=4988 from this can select nearest ans...

Gautam Sharma said:
1 decade ago

At First, Multiply 6500x6=39000 (bcoz avg is asking in Q)

Then, add all the 5 sale i.e 34009,

Deduct 39000 from the total sale i.e.34009, it becomes 4991.

Then, add all the 5 sale i.e 34009,

Deduct 39000 from the total sale i.e.34009, it becomes 4991.

Pankaj said:
1 decade ago

6435+6927+6855+7230+6562= 34009

6500*7 =39000

39000-34009 =4991

6500*7 =39000

39000-34009 =4991

Bhavana said:
1 decade ago

Why do we multiply 6 with 6500.

Naveen kumar said:
1 decade ago

Hi friends...

Here is the shortcut method to find this problem...

given average sale for 6 months is 6500..

but we don't know 6 month reading...let it be x..

now,according to the formula...

(6435+6927+6855+7230+6562+x) /6 = 6500

34009 + x = 39000

x = 4991.

Here is the shortcut method to find this problem...

given average sale for 6 months is 6500..

but we don't know 6 month reading...let it be x..

now,according to the formula...

(6435+6927+6855+7230+6562+x) /6 = 6500

34009 + x = 39000

x = 4991.

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