# Verbal Reasoning - Data Sufficiency - Discussion

Discussion Forum : Data Sufficiency - Section 1 (Q.No. 2)

*Directions to Solve*

In each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question. Read both the statements and

Give answer

- (A) If the data in statement I alone are sufficient to answer the question, while the data in statement II alone are not sufficient to answer the question
- (B) If the data in statement II alone are sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question
- (C) If the data either in statement I alone or in statement II alone are sufficient to answer the question
- (D) If the data given in both statements I and II together are not sufficient to answer the question and
- (E) If the data in both statements I and II together are necessary to answer the question.

2.

**Question: ** What will be the total weight of 10 poles, each of the same weight ?

**Statements:**

- One-fourth of the weight of each pole is 5 kg.
- The total weight of three poles is 20 kilograms more than the total weight of two poles.

Answer: Option

Explanation:

From I, we conclude that weight of each pole = (4x5) kg = 20 kg.

So, total weight of 10 poles = (20 x 10) kg = 200 kg.

From II, we conclude that:

Weight of each pole = (weight of 3 poles) - (weight of 2 poles) = 20 kg.

So, total weight of 10 pojes = (20 x 10) kg = 200 kg.

Discussion:

25 comments Page 3 of 3.
Eswar said:
1 decade ago

Any new methods for solving these questions?

Ponmuneeswariganesan said:
1 decade ago

Is any technique is available to solve the data sufficiency problems?

Harry said:
1 decade ago

Explanation for statement II:

Let the weight of one pole be x

So x + x = a ( a is weight of two poles & each pole is of same weight)

i.e 2x = a

Similarly 3x = a + 20 ( total weight of three poles is 20 kilograms more than the total weight of two poles)

i.e 3x - 20 = a

So 2x = 3x - 20

x = 20.

Let the weight of one pole be x

So x + x = a ( a is weight of two poles & each pole is of same weight)

i.e 2x = a

Similarly 3x = a + 20 ( total weight of three poles is 20 kilograms more than the total weight of two poles)

i.e 3x - 20 = a

So 2x = 3x - 20

x = 20.

Senthil said:
1 decade ago

I need explanation of Statement II

Weight of each pole = (weight of 3 poles) - (weight of 2 poles) = 20 kg.

Weight of each pole = (weight of 3 poles) - (weight of 2 poles) = 20 kg.

Saurabh said:
1 decade ago

Answer should be both I and II are sufficient.

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