# Verbal Reasoning - Data Sufficiency - Discussion

Discussion Forum : Data Sufficiency - Section 1 (Q.No. 2)

*Directions to Solve*

In each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question. Read both the statements and

Give answer

- (A) If the data in statement I alone are sufficient to answer the question, while the data in statement II alone are not sufficient to answer the question
- (B) If the data in statement II alone are sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question
- (C) If the data either in statement I alone or in statement II alone are sufficient to answer the question
- (D) If the data given in both statements I and II together are not sufficient to answer the question and
- (E) If the data in both statements I and II together are necessary to answer the question.

2.

**Question: ** What will be the total weight of 10 poles, each of the same weight ?

**Statements:**

- One-fourth of the weight of each pole is 5 kg.
- The total weight of three poles is 20 kilograms more than the total weight of two poles.

Answer: Option

Explanation:

From I, we conclude that weight of each pole = (4x5) kg = 20 kg.

So, total weight of 10 poles = (20 x 10) kg = 200 kg.

From II, we conclude that:

Weight of each pole = (weight of 3 poles) - (weight of 2 poles) = 20 kg.

So, total weight of 10 pojes = (20 x 10) kg = 200 kg.

Discussion:

25 comments Page 1 of 3.
Harry said:
1 decade ago

Explanation for statement II:

Let the weight of one pole be x

So x + x = a ( a is weight of two poles & each pole is of same weight)

i.e 2x = a

Similarly 3x = a + 20 ( total weight of three poles is 20 kilograms more than the total weight of two poles)

i.e 3x - 20 = a

So 2x = 3x - 20

x = 20.

Let the weight of one pole be x

So x + x = a ( a is weight of two poles & each pole is of same weight)

i.e 2x = a

Similarly 3x = a + 20 ( total weight of three poles is 20 kilograms more than the total weight of two poles)

i.e 3x - 20 = a

So 2x = 3x - 20

x = 20.

Riya said:
8 years ago

Similarly 3x = a + 20 (Total weight of three poles is 20 kilograms more than the total weight of two poles).

i.e 3x-20 = a.

So 2x = 3x-20.

x = 20.

I am not clear with this step and what is the meaning of total weight of three poles is 20 kilograms more than the total weight of two poles.

i.e 3x-20 = a.

So 2x = 3x-20.

x = 20.

I am not clear with this step and what is the meaning of total weight of three poles is 20 kilograms more than the total weight of two poles.

Parth said:
5 years ago

In statement I, what if the weight of the pole is not uniform throughout?

I mean: what if the total weight of the pole is not 4x5? There is a chance that the pole is tapered! Right?

Please correct me, If I am wrong.

I mean: what if the total weight of the pole is not 4x5? There is a chance that the pole is tapered! Right?

Please correct me, If I am wrong.

Abhishek Kumar said:
6 years ago

For the second point, main point to look for is the weight of each pole are same, so the weight of 3 poles is more than the weight of two poles, it means they are giving the weight of each pole which is same, 20.

Vinay said:
3 years ago

Here we are not combining both statements. Option C is right because by reading each statement individually we can conclude. Option E is only correct when we use two statements together to conclude.

(1)

Dattu said:
6 years ago

St2: Wt of 3 poles = 20 kgs + wt of 2 poles.

wt of 3 poles - wt of 2 poles = 20,

wt of 1 pole = 20kgs,

finally , wt of 10 poles = 10 * 20 = 200 kgs.

Ans is both st1, st2 are sufficient.

wt of 3 poles - wt of 2 poles = 20,

wt of 1 pole = 20kgs,

finally , wt of 10 poles = 10 * 20 = 200 kgs.

Ans is both st1, st2 are sufficient.

Shahid said:
7 years ago

Statement one is alone to solve this.

Logically if 1/4 of weight is 5 Kg then obviously 4/4 is 20 kg. So 20 kg is the weight of one pole then 200 kg is the weight of 10 poles.

Logically if 1/4 of weight is 5 Kg then obviously 4/4 is 20 kg. So 20 kg is the weight of one pole then 200 kg is the weight of 10 poles.

Charmi said:
2 years ago

Absolutely C is the correct answer. Because both statements are separate from each other.

So we consider only one statement to prove the question either 1 or 2.

So we consider only one statement to prove the question either 1 or 2.

HEMALATHA said:
3 years ago

Option (A).

1/4 of each pole weight = 5 kg.

Then 1 pole weight = 5*4= 20 kg.

1 pole weight is = 20 kg.

Then 10 poles weight= 10 pole*20 kg.

That is = 200 kg.

1/4 of each pole weight = 5 kg.

Then 1 pole weight = 5*4= 20 kg.

1 pole weight is = 20 kg.

Then 10 poles weight= 10 pole*20 kg.

That is = 200 kg.

(2)

Priya said:
7 years ago

Can you please explain the equation :

Similarly 3x = a + 20 ( total weight of three poles is 20 kilograms more than the total weight of two poles).

Similarly 3x = a + 20 ( total weight of three poles is 20 kilograms more than the total weight of two poles).

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