Verbal Reasoning - Data Sufficiency - Discussion
Discussion Forum : Data Sufficiency - Section 1 (Q.No. 2)
Directions to Solve
In each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question. Read both the statements and
Give answer
- (A) If the data in statement I alone are sufficient to answer the question, while the data in statement II alone are not sufficient to answer the question
- (B) If the data in statement II alone are sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question
- (C) If the data either in statement I alone or in statement II alone are sufficient to answer the question
- (D) If the data given in both statements I and II together are not sufficient to answer the question and
- (E) If the data in both statements I and II together are necessary to answer the question.
2.
Question: What will be the total weight of 10 poles, each of the same weight ?
Statements:
- One-fourth of the weight of each pole is 5 kg.
- The total weight of three poles is 20 kilograms more than the total weight of two poles.
Answer: Option
Explanation:
From I, we conclude that weight of each pole = (4x5) kg = 20 kg.
So, total weight of 10 poles = (20 x 10) kg = 200 kg.
From II, we conclude that:
Weight of each pole = (weight of 3 poles) - (weight of 2 poles) = 20 kg.
So, total weight of 10 pojes = (20 x 10) kg = 200 kg.
Discussion:
25 comments Page 1 of 3.
Saurabh said:
1 decade ago
Answer should be both I and II are sufficient.
Senthil said:
1 decade ago
I need explanation of Statement II
Weight of each pole = (weight of 3 poles) - (weight of 2 poles) = 20 kg.
Weight of each pole = (weight of 3 poles) - (weight of 2 poles) = 20 kg.
Harry said:
1 decade ago
Explanation for statement II:
Let the weight of one pole be x
So x + x = a ( a is weight of two poles & each pole is of same weight)
i.e 2x = a
Similarly 3x = a + 20 ( total weight of three poles is 20 kilograms more than the total weight of two poles)
i.e 3x - 20 = a
So 2x = 3x - 20
x = 20.
Let the weight of one pole be x
So x + x = a ( a is weight of two poles & each pole is of same weight)
i.e 2x = a
Similarly 3x = a + 20 ( total weight of three poles is 20 kilograms more than the total weight of two poles)
i.e 3x - 20 = a
So 2x = 3x - 20
x = 20.
Ponmuneeswariganesan said:
1 decade ago
Is any technique is available to solve the data sufficiency problems?
Eswar said:
1 decade ago
Any new methods for solving these questions?
Riya said:
9 years ago
Similarly 3x = a + 20 (Total weight of three poles is 20 kilograms more than the total weight of two poles).
i.e 3x-20 = a.
So 2x = 3x-20.
x = 20.
I am not clear with this step and what is the meaning of total weight of three poles is 20 kilograms more than the total weight of two poles.
i.e 3x-20 = a.
So 2x = 3x-20.
x = 20.
I am not clear with this step and what is the meaning of total weight of three poles is 20 kilograms more than the total weight of two poles.
Shahid said:
8 years ago
Statement one is alone to solve this.
Logically if 1/4 of weight is 5 Kg then obviously 4/4 is 20 kg. So 20 kg is the weight of one pole then 200 kg is the weight of 10 poles.
Logically if 1/4 of weight is 5 Kg then obviously 4/4 is 20 kg. So 20 kg is the weight of one pole then 200 kg is the weight of 10 poles.
Suman raj said:
8 years ago
From both I and II, we find that the weight of 10 poles. So, the answer should be both I and II are sufficient.
Durgesh said:
8 years ago
Answer should be both I and II are sufficient.
Priya said:
8 years ago
Can you please explain the equation :
Similarly 3x = a + 20 ( total weight of three poles is 20 kilograms more than the total weight of two poles).
Similarly 3x = a + 20 ( total weight of three poles is 20 kilograms more than the total weight of two poles).
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