Verbal Reasoning - Data Sufficiency - Discussion
Discussion Forum : Data Sufficiency - Section 1 (Q.No. 2)
Directions to Solve
In each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question. Read both the statements and
Give answer
- (A) If the data in statement I alone are sufficient to answer the question, while the data in statement II alone are not sufficient to answer the question
- (B) If the data in statement II alone are sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question
- (C) If the data either in statement I alone or in statement II alone are sufficient to answer the question
- (D) If the data given in both statements I and II together are not sufficient to answer the question and
- (E) If the data in both statements I and II together are necessary to answer the question.
2.
Question: What will be the total weight of 10 poles, each of the same weight ?
Statements:
- One-fourth of the weight of each pole is 5 kg.
- The total weight of three poles is 20 kilograms more than the total weight of two poles.
Answer: Option
Explanation:
From I, we conclude that weight of each pole = (4x5) kg = 20 kg.
So, total weight of 10 poles = (20 x 10) kg = 200 kg.
From II, we conclude that:
Weight of each pole = (weight of 3 poles) - (weight of 2 poles) = 20 kg.
So, total weight of 10 pojes = (20 x 10) kg = 200 kg.
Discussion:
25 comments Page 2 of 3.
Rohit Patil said:
7 years ago
The should be Both I and II are sufficient.
Abhishek Kumar said:
7 years ago
For the second point, main point to look for is the weight of each pole are same, so the weight of 3 poles is more than the weight of two poles, it means they are giving the weight of each pole which is same, 20.
Dattu said:
8 years ago
St2: Wt of 3 poles = 20 kgs + wt of 2 poles.
wt of 3 poles - wt of 2 poles = 20,
wt of 1 pole = 20kgs,
finally , wt of 10 poles = 10 * 20 = 200 kgs.
Ans is both st1, st2 are sufficient.
wt of 3 poles - wt of 2 poles = 20,
wt of 1 pole = 20kgs,
finally , wt of 10 poles = 10 * 20 = 200 kgs.
Ans is both st1, st2 are sufficient.
Saurabh said:
1 decade ago
Answer should be both I and II are sufficient.
Abhishek singh said:
8 years ago
The Answer should be both I and II are sufficient.
Shekhar patel said:
9 years ago
According to me, the answer is both l and ll are sufficient.
Priya said:
9 years ago
Can you please explain the equation :
Similarly 3x = a + 20 ( total weight of three poles is 20 kilograms more than the total weight of two poles).
Similarly 3x = a + 20 ( total weight of three poles is 20 kilograms more than the total weight of two poles).
Durgesh said:
9 years ago
Answer should be both I and II are sufficient.
Suman raj said:
9 years ago
From both I and II, we find that the weight of 10 poles. So, the answer should be both I and II are sufficient.
Shahid said:
9 years ago
Statement one is alone to solve this.
Logically if 1/4 of weight is 5 Kg then obviously 4/4 is 20 kg. So 20 kg is the weight of one pole then 200 kg is the weight of 10 poles.
Logically if 1/4 of weight is 5 Kg then obviously 4/4 is 20 kg. So 20 kg is the weight of one pole then 200 kg is the weight of 10 poles.
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