Verbal Reasoning - Cube and Cuboid

There are 128 cubes with me which are coloured according to two schemes viz.

  1. 64 cubes each having two red adjacent faces and one yellow and other blue on their opposite faces while green on the rest.
  2. 64 cubes each having two adjacent blue faces and one red and other green on their opposite faces, while red on the rest. They are then mixed up.
1. 

How many cubes have at least two coloured red faces each ?

A. 0
B. 32
C. 64
D. 128

Answer: Option D

Explanation:

64 and 64 cubes of both types of cubes are such who have at least two coloured faces red each.

Therefore, total number of the required cubes is 128.


2. 

What is the total number of red faces ?

A. 0
B. 64
C. 320
D. 128

Answer: Option C

Explanation:

No. of red faces among first 64 cubes = 128

No. of red faces among second 64 cubes = 192

Therefore, total number of red faces = 128 + 192 = 320


3. 

How many cubes have two adjacent blue faces each ?

A. 64
B. 32
C. 0
D. 128

Answer: Option A

Explanation:

Second 64 cubes are such each of whose two faces are blue.


4. 

How many cubes have only one red face each ?

A. 128
B. 32
C. 64
D. None

Answer: Option D

Explanation:

Out of 128 cubes no cube have only one face is red


5. 

Which two colours have the same number of faces ?

A. Red and Yellow
B. Blue and Green
C. Red and Green
D. Red and Blue

Answer: Option B

Explanation:

First 64 cubes are such each of whose two faces are green and second 64 cubes are such each of whose two faces are blue.

Therefore, green and blue colours have the same number of faces.