# Verbal Reasoning - Cube and Cuboid - Discussion

There are 128 cubes with me which are coloured according to two schemes viz.

1. 64 cubes each having two red adjacent faces and one yellow and other blue on their opposite faces while green on the rest.
2. 64 cubes each having two adjacent blue faces and one red and other green on their opposite faces, while red on the rest. They are then mixed up.

2.

What is the total number of red faces ?

 [A]. 0 [B]. 64 [C]. 320 [D]. 128

Explanation:

No. of red faces among first 64 cubes = 128

No. of red faces among second 64 cubes = 192

Therefore, total number of red faces = 128 + 192 = 320

 Krishna said: (Sep 12, 2010) How do the second 64 cubes contain (64*3=192). How it is 3 faces with red colour?

 Rohitkr said: (Aug 5, 2011) Ans should be 256. (64*2+64*2) No. of red faces among first cube = 64*2 = 128. No. of red faces among Second cube = 64*2 = 128. ---------------- Total no. of red faces = 256. ----------------

 Shekhar Ghate said: (Nov 6, 2011) The second cube have three faces red. Two opposite to two adjacent blue (rest in question) and one opposite to green. Therefore 320 is correct answer.

 Don said: (Aug 16, 2014) No.of red faces in 1st cube(64*2) = 128 because 2 red colours are painted. No.of red faces in 2nd cube(64*3) = 192 because 3 red colours are painted. Total no.of red faces = 320.

 Sanyam said: (Jun 15, 2016) According to me, There are 2 faces colored red in the 1st cube. So 32 red faces are there in the first cube. In the 2nd cube, there are 3 red colored faces. So red faces in the second cube = 48. So total no of red faces = 48 + 32 = 80.

 Madhura said: (Feb 12, 2019) How come 3 red faces in 2nd cube, can anyone explain?

 Vivek said: (Oct 30, 2020) In the second cube we have, 2 adjacent faces with blue, 1 face with red and opposite to that 1 green colour is there. So 4 faces are coloured as of now. The remaining 2 faces are colored with red. So total of 3 red faces are there.