Discussion :: Cube and Cuboid - Cube and Cuboid 8 (Q.No.2)
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There are 128 cubes with me which are coloured according to two schemes viz.
- 64 cubes each having two red adjacent faces and one yellow and other blue on their opposite faces while green on the rest.
- 64 cubes each having two adjacent blue faces and one red and other green on their opposite faces, while red on the rest. They are then mixed up.
Krishna said: (Sep 12, 2010) | |
How do the second 64 cubes contain (64*3=192). How it is 3 faces with red colour? |
Rohitkr said: (Aug 5, 2011) | |
Ans should be 256. (64*2+64*2) No. of red faces among first cube = 64*2 = 128. No. of red faces among Second cube = 64*2 = 128. ---------------- Total no. of red faces = 256. ---------------- |
Shekhar Ghate said: (Nov 6, 2011) | |
The second cube have three faces red. Two opposite to two adjacent blue (rest in question) and one opposite to green. Therefore 320 is correct answer. |
Don said: (Aug 16, 2014) | |
No.of red faces in 1st cube(64*2) = 128 because 2 red colours are painted. No.of red faces in 2nd cube(64*3) = 192 because 3 red colours are painted. Total no.of red faces = 320. |
Sanyam said: (Jun 15, 2016) | |
According to me, There are 2 faces colored red in the 1st cube. So 32 red faces are there in the first cube. In the 2nd cube, there are 3 red colored faces. So red faces in the second cube = 48. So total no of red faces = 48 + 32 = 80. |
Madhura said: (Feb 12, 2019) | |
How come 3 red faces in 2nd cube, can anyone explain? |
Vivek said: (Oct 30, 2020) | |
In the second cube we have, 2 adjacent faces with blue, 1 face with red and opposite to that 1 green colour is there. So 4 faces are coloured as of now. The remaining 2 faces are colored with red. So total of 3 red faces are there. |
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