Verbal Reasoning - Cube and Cuboid - Discussion

There are 128 cubes with me which are coloured according to two schemes viz.

  1. 64 cubes each having two red adjacent faces and one yellow and other blue on their opposite faces while green on the rest.
  2. 64 cubes each having two adjacent blue faces and one red and other green on their opposite faces, while red on the rest. They are then mixed up.


How many cubes have at least two coloured red faces each ?

[A]. 0
[B]. 32
[C]. 64
[D]. 128

Answer: Option D


64 and 64 cubes of both types of cubes are such who have at least two coloured faces red each.

Therefore, total number of the required cubes is 128.

Rahul Pareek said: (Jan 10, 2011)  
Explanation is not clear!.

Please explain by figure if possible.

Ramakhanna said: (Jun 2, 2011)  
@Rahul, dont use this step a^3=64. a==>4.

Instead consider the given conditions for the single cube. Then you will easily arrive at the answer.

Keerthi said: (Jan 10, 2012)  
Please explain it little more clear.

Swetha said: (Jan 21, 2012)  
Please explain with help of figure.

Mahendra said: (Dec 13, 2013)  
In the given information:-

For each small cube we have two red faces, one yellow, other blue and two green colored faces.

So for first 64 cubes part we have 64 small cubes having 2 red colored faces.

Riya said: (Aug 6, 2015)  
Not clear please explain in detail.

Arka Saha said: (Jan 15, 2016)  
"64 cubes each" having two red adjacent faces is mentioned in both the two statements. So all 128 cubes have two side as red.

Aishwarya Jadhav said: (Apr 25, 2017)  
In 2nd statement, it clearly mentions that two adjacent blue faces and one red the how the answer is 128?

Aman said: (Oct 28, 2020)  
Please give the full explanation.

Jayabai said: (Nov 11, 2020)  
I am not understanding. Please explain to me.

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