Verbal Reasoning - Cube and Cuboid - Discussion

Discussion Forum : Cube and Cuboid - Cube and Cuboid 8 (Q.No. 1)
Directions to Solve

There are 128 cubes with me which are coloured according to two schemes viz.

  1. 64 cubes each having two red adjacent faces and one yellow and other blue on their opposite faces while green on the rest.
  2. 64 cubes each having two adjacent blue faces and one red and other green on their opposite faces, while red on the rest. They are then mixed up.

1.
How many cubes have at least two coloured red faces each ?
0
32
64
128
Answer: Option
Explanation:

64 and 64 cubes of both types of cubes are such who have at least two coloured faces red each.

Therefore, total number of the required cubes is 128.

Discussion:
10 comments Page 1 of 1.

Rahul Pareek said:   1 decade ago
Explanation is not clear!.

Please explain by figure if possible.
(1)

Ramakhanna said:   1 decade ago
@Rahul, dont use this step a^3=64. a==>4.

Instead consider the given conditions for the single cube. Then you will easily arrive at the answer.
(1)

Keerthi said:   1 decade ago
Please explain it little more clear.
(1)

Swetha said:   1 decade ago
Please explain with help of figure.
(1)

Riya said:   1 decade ago
Not clear please explain in detail.
(1)

Aishwarya jadhav said:   8 years ago
In 2nd statement, it clearly mentions that two adjacent blue faces and one red the how the answer is 128?
(1)

Mahendra said:   1 decade ago
In the given information:-

For each small cube we have two red faces, one yellow, other blue and two green colored faces.

So for first 64 cubes part we have 64 small cubes having 2 red colored faces.

Arka Saha said:   10 years ago
"64 cubes each" having two red adjacent faces is mentioned in both the two statements. So all 128 cubes have two side as red.

Aman said:   5 years ago
Please give the full explanation.

Jayabai said:   5 years ago
I am not understanding. Please explain to me.

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