# Verbal Reasoning - Cube and Cuboid

- Cube and Cuboid - Introduction
- Cube and Cuboid - Cube and Cuboid 1
- Cube and Cuboid - Cube and Cuboid 2
- Cube and Cuboid - Cube and Cuboid 3
- Cube and Cuboid - Cube and Cuboid 4
- Cube and Cuboid - Cube and Cuboid 5
- Cube and Cuboid - Cube and Cuboid 6
- Cube and Cuboid - Cube and Cuboid 7
- Cube and Cuboid - Cube and Cuboid 8
- Cube and Cuboid - Cube and Cuboid 9

*Directions to Solve*

The following questions are based on the information given below:

All the opposite faces of a big cube are coloured with red, black and green colours. After that is cut into 64 small equal cubes.

Number of small cubes having one face green and the other one is either red or black = 8 x 2 = 16

Number of small cubes having no face coloured = (x - 2)^{3}

= (4 - 2)^{3}

= 8

Number of small cubes having three faces coloured = 1 at each corner

= 1 x 8

= 8

>Number of small cubes having only one face coloured = 4 from each face

= 4 x 6

= 24

Number of small cubes having two faces coloured = 8 + 8 + 4 + 4 = 24

and Number of small cubes having only one face coloured = 4 x 6 = 24

and Number of small cubes having no face coloured = 4 + 4 = 8

Therefore, total number of small cubes whose at the most two faces are coloured = 24 + 24 + 8 = 56.