Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 2)
2.
Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?
Answer: Option
Explanation:
Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city A.
Then, 2x + 3y = 77 ...(i) and
3x + 2y = 73 ...(ii)
Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.
Putting y = 17 in (i), we get: x = 13.
Discussion:
49 comments Page 4 of 5.
Bujji said:
1 decade ago
It is wrong antony. In options 17 and 13 is also there. So your method is wrong.
Gangadhar said:
1 decade ago
Vijay method is correct.
Deep said:
1 decade ago
Vijay why did you first multiply by 3 and then by 2 why not the reverse... How would you manage the negative output when you multiply first line by 2 and second line by 3
i.e 4x + 6y
9x + 6x
-------------
Minus = 5x ?
Don't know if I made sense with my question.
i.e 4x + 6y
9x + 6x
-------------
Minus = 5x ?
Don't know if I made sense with my question.
Madhu said:
1 decade ago
@Vijay
You are method is so good. easy way to understand..in Vijay method if any x,y coefficient should made equal to the values. Because we find x,y values..thats why he multiple 3 with first equation and 2 with second equation.
You are method is so good. easy way to understand..in Vijay method if any x,y coefficient should made equal to the values. Because we find x,y values..thats why he multiple 3 with first equation and 2 with second equation.
Anam charan patra said:
1 decade ago
Please explain why multiply 3 series (i) and 2 multiply series (ii)?
Ramkumar said:
1 decade ago
Its very simple.
It is a optional based solution .
There forms :
2x+3y = 77.
3x+2y = 73 (then we find x and y).
Simply check with A B C D options.
Now option B is: 13, 17 is satisfies the above equations.
It is a optional based solution .
There forms :
2x+3y = 77.
3x+2y = 73 (then we find x and y).
Simply check with A B C D options.
Now option B is: 13, 17 is satisfies the above equations.
Jitendra said:
1 decade ago
New method by @Antony is really good and a short-cut way to find the solution.
Rashed said:
9 years ago
Hi, I'm not much good in maths but can anybody tell me how we are multiplying these equations with 3 and 2? Where these 3 and 2 comes from?
Dazedandconfused said:
1 decade ago
For some reason, this seems complicated to me. What is the purpose of these tests?
Sajid khan said:
1 decade ago
2x + 3y = 77.
3x + 2y = 73.
Solution :
2x + 3y = 77 (i)multiplying by 3.
6x + 9y = 231.
3x + 2y = 73 (ii)multiplying by 2.
6x + 4y = 146.
Now subtract its,
6x + 9y = 231.
6x - 4y = -146.
0x + 5y = 85.
5y = 85.
y = 85/5.
Ans y = 17.
Now put y value on the equation (i).
6x + 9(17) = 231.
6x + 153 = 231.
6x + 153 - 231 = 0.
6x - 78 = 0.
x = 78/6.
x = 13.
Solution set is { 13 , 17 }.
3x + 2y = 73.
Solution :
2x + 3y = 77 (i)multiplying by 3.
6x + 9y = 231.
3x + 2y = 73 (ii)multiplying by 2.
6x + 4y = 146.
Now subtract its,
6x + 9y = 231.
6x - 4y = -146.
0x + 5y = 85.
5y = 85.
y = 85/5.
Ans y = 17.
Now put y value on the equation (i).
6x + 9(17) = 231.
6x + 153 = 231.
6x + 153 - 231 = 0.
6x - 78 = 0.
x = 78/6.
x = 13.
Solution set is { 13 , 17 }.
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