Verbal Reasoning - Arithmetic Reasoning - Discussion

Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 2)
2.
Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?
Rs. 4, Rs. 23
Rs. 13, Rs. 17
Rs. 15, Rs. 14
Rs. 17, Rs. 13
Answer: Option
Explanation:

Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city A.

Then, 2x + 3y = 77 ...(i) and

3x + 2y = 73 ...(ii)

Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.

Putting y = 17 in (i), we get: x = 13.

Discussion:
50 comments Page 3 of 5.

Kamaho said:   9 years ago
How 3 and 2 is there?

Why do we multiply with 3&2 why not 2&3? everyone know 13&17 is the correct answer. But how & where do we get that 3 & 2 why not 2&3 anyone who can explain this for me? Yes, we know if we multiply by 3 & 2 we get an answer but how do we got that?

Priyan said:   9 years ago
How to get 85?

Not understanding it.

Siyad said:   9 years ago
@Kamaho

We have to make either x or y value 0 to get one's value.

So multiplying (i) with 3 and (ii) with 2 we will get x part 0 by equating both equations [ (i) - (ii) ] then only we get 5y=85 further values.

Also, we can multiply (i) with 2 and (ii) with 3.
Then by equating both, we will get 5x=65 then x=65/5..... x=13.

The purpose of multiplying the equations is to make either x or y equal, then by equating we will get either x or y =0.
You can take any no. For multiply, but make values of both x or both y equal.

Hope you will understand.

Sunil gampa said:   9 years ago
Please explain clearly how to take x y values in an equation?

Vanshika said:   8 years ago
How do we get to know that 1st equation will be multiplied 3 and second by 2?

SINDHU BATTULA said:   3 weeks ago
Thank you everyone for explaining the answer.

M.Haseeb Sahal Shah said:   1 decade ago
2x+3y = 77.
2x = 77 -3y.
x = 77 - 3y /2 ... (1).

3x+2y = 73.

Put x value,

3(77 - 3y /2)+ 2y = 73.
3(77 - 3y)= 2(73-2y).
231-9y = 146-4y.
231-146 = -4y+9y.
85 = 5y.
85/5 =y.
17 = y.

x = 77 - 3y /2 ... (1).
x = 77 - 3(17) /2.
x = 77 - 51 /2.
x = 26/2.
x = 13.

B is answer 13, 17.

Ladyno said:   1 decade ago
I am truly lost, please help. Where does (i) and (ii) fit in?

M. Iyyammal said:   1 decade ago
I cant get this, please explain (1) and (ii).

Vijaya said:   1 decade ago
2x + 3y = 77 multiply this line with 3 so it becomes
6x + 9y = 231-----------(i)

3x + 2y = 73 multiply this line with 2 so it becomes
6x + 4y = 146 -------------(ii)

now solve both the equestion (i) and (ii)
6x + 9y = 231
6x + 4y = 146
----------------
ox + 5y = 85

y = 85/5 = 17

in the same way do for X ..


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