Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 2)
2.
Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?
Answer: Option
Explanation:
Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city A.
Then, 2x + 3y = 77 ...(i) and
3x + 2y = 73 ...(ii)
Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.
Putting y = 17 in (i), we get: x = 13.
Discussion:
49 comments Page 1 of 5.
Sartaj said:
1 decade ago
I cant get this, please explain.
Ladyno said:
1 decade ago
I am truly lost, please help. Where does (i) and (ii) fit in?
M. Iyyammal said:
1 decade ago
I cant get this, please explain (1) and (ii).
Vijaya said:
1 decade ago
2x + 3y = 77 multiply this line with 3 so it becomes
6x + 9y = 231-----------(i)
3x + 2y = 73 multiply this line with 2 so it becomes
6x + 4y = 146 -------------(ii)
now solve both the equestion (i) and (ii)
6x + 9y = 231
6x + 4y = 146
----------------
ox + 5y = 85
y = 85/5 = 17
in the same way do for X ..
6x + 9y = 231-----------(i)
3x + 2y = 73 multiply this line with 2 so it becomes
6x + 4y = 146 -------------(ii)
now solve both the equestion (i) and (ii)
6x + 9y = 231
6x + 4y = 146
----------------
ox + 5y = 85
y = 85/5 = 17
in the same way do for X ..
Antony said:
1 decade ago
New method
3 tickets A to B
2 tickets A to c
that's 77/5 = 15.4
3 tickets A to B
2 tickets A to C
that's 73/5 = 14.6
so 15.4+14.6 = 30
Ans: 13 + 17 = 30 --- (B)
3 tickets A to B
2 tickets A to c
that's 77/5 = 15.4
3 tickets A to B
2 tickets A to C
that's 73/5 = 14.6
so 15.4+14.6 = 30
Ans: 13 + 17 = 30 --- (B)
Bujji said:
1 decade ago
It is wrong antony. In options 17 and 13 is also there. So your method is wrong.
Gangadhar said:
1 decade ago
Vijay method is correct.
Deep said:
1 decade ago
Vijay why did you first multiply by 3 and then by 2 why not the reverse... How would you manage the negative output when you multiply first line by 2 and second line by 3
i.e 4x + 6y
9x + 6x
-------------
Minus = 5x ?
Don't know if I made sense with my question.
i.e 4x + 6y
9x + 6x
-------------
Minus = 5x ?
Don't know if I made sense with my question.
Satwant said:
1 decade ago
Let, A to B fare as X and A to C as Y
(2x + 3y = 77)X 3 ---------------(1 line)
(3x + 2y = 73)X 2 ---------------(2 line)
now, after multiplications, we get
6x + 9y = 231---------------(1 line)
6x + 4y = 146---------------(2 line)
now, after change the signs and solve the equation, we will get
6x + 9y = 231
-6x - 4y =-146
----------------
ox + 5y = 85
OR,5y = 85
Y= 85/5
OR, Y= 17
NOW, put the value of y in any line, for Eg. in first line, as under:-
2x+3y=77------(1 line)
2x+3(17)=77
2x+51=77
OR, 2x=77-51
2x=26
x=26/2
x=13
SO,
13 and 17 is the answer
(2x + 3y = 77)X 3 ---------------(1 line)
(3x + 2y = 73)X 2 ---------------(2 line)
now, after multiplications, we get
6x + 9y = 231---------------(1 line)
6x + 4y = 146---------------(2 line)
now, after change the signs and solve the equation, we will get
6x + 9y = 231
-6x - 4y =-146
----------------
ox + 5y = 85
OR,5y = 85
Y= 85/5
OR, Y= 17
NOW, put the value of y in any line, for Eg. in first line, as under:-
2x+3y=77------(1 line)
2x+3(17)=77
2x+51=77
OR, 2x=77-51
2x=26
x=26/2
x=13
SO,
13 and 17 is the answer
(1)
Madhu said:
1 decade ago
@Vijay
You are method is so good. easy way to understand..in Vijay method if any x,y coefficient should made equal to the values. Because we find x,y values..thats why he multiple 3 with first equation and 2 with second equation.
You are method is so good. easy way to understand..in Vijay method if any x,y coefficient should made equal to the values. Because we find x,y values..thats why he multiple 3 with first equation and 2 with second equation.
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