Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 2)
2.
Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?
Answer: Option
Explanation:
Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city A.
Then, 2x + 3y = 77 ...(i) and
3x + 2y = 73 ...(ii)
Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.
Putting y = 17 in (i), we get: x = 13.
Discussion:
49 comments Page 2 of 5.
Anam charan patra said:
1 decade ago
Please explain why multiply 3 series (i) and 2 multiply series (ii)?
Ramkumar said:
1 decade ago
Its very simple.
It is a optional based solution .
There forms :
2x+3y = 77.
3x+2y = 73 (then we find x and y).
Simply check with A B C D options.
Now option B is: 13, 17 is satisfies the above equations.
It is a optional based solution .
There forms :
2x+3y = 77.
3x+2y = 73 (then we find x and y).
Simply check with A B C D options.
Now option B is: 13, 17 is satisfies the above equations.
Jitendra said:
1 decade ago
New method by @Antony is really good and a short-cut way to find the solution.
M.Haseeb Sahal Shah said:
1 decade ago
2x+3y = 77.
2x = 77 -3y.
x = 77 - 3y /2 ... (1).
3x+2y = 73.
Put x value,
3(77 - 3y /2)+ 2y = 73.
3(77 - 3y)= 2(73-2y).
231-9y = 146-4y.
231-146 = -4y+9y.
85 = 5y.
85/5 =y.
17 = y.
x = 77 - 3y /2 ... (1).
x = 77 - 3(17) /2.
x = 77 - 51 /2.
x = 26/2.
x = 13.
B is answer 13, 17.
2x = 77 -3y.
x = 77 - 3y /2 ... (1).
3x+2y = 73.
Put x value,
3(77 - 3y /2)+ 2y = 73.
3(77 - 3y)= 2(73-2y).
231-9y = 146-4y.
231-146 = -4y+9y.
85 = 5y.
85/5 =y.
17 = y.
x = 77 - 3y /2 ... (1).
x = 77 - 3(17) /2.
x = 77 - 51 /2.
x = 26/2.
x = 13.
B is answer 13, 17.
Dazedandconfused said:
1 decade ago
For some reason, this seems complicated to me. What is the purpose of these tests?
Sajid khan said:
1 decade ago
2x + 3y = 77.
3x + 2y = 73.
Solution :
2x + 3y = 77 (i)multiplying by 3.
6x + 9y = 231.
3x + 2y = 73 (ii)multiplying by 2.
6x + 4y = 146.
Now subtract its,
6x + 9y = 231.
6x - 4y = -146.
0x + 5y = 85.
5y = 85.
y = 85/5.
Ans y = 17.
Now put y value on the equation (i).
6x + 9(17) = 231.
6x + 153 = 231.
6x + 153 - 231 = 0.
6x - 78 = 0.
x = 78/6.
x = 13.
Solution set is { 13 , 17 }.
3x + 2y = 73.
Solution :
2x + 3y = 77 (i)multiplying by 3.
6x + 9y = 231.
3x + 2y = 73 (ii)multiplying by 2.
6x + 4y = 146.
Now subtract its,
6x + 9y = 231.
6x - 4y = -146.
0x + 5y = 85.
5y = 85.
y = 85/5.
Ans y = 17.
Now put y value on the equation (i).
6x + 9(17) = 231.
6x + 153 = 231.
6x + 153 - 231 = 0.
6x - 78 = 0.
x = 78/6.
x = 13.
Solution set is { 13 , 17 }.
Aneri Desai said:
1 decade ago
s2b(2) & s2a(3) = 77.
s2b(3) & s2a(2) = 73.
s2b=x=? & s2a=y=?
4x+6y = 154.
9x+6y = 219.
-5x = -65.
x = 13.
y = 17.
s2b(3) & s2a(2) = 73.
s2b=x=? & s2a=y=?
4x+6y = 154.
9x+6y = 219.
-5x = -65.
x = 13.
y = 17.
Reghu R said:
1 decade ago
2x+3y = 77 --------- i.
3x+2y = 73 --------- ii.
---------
i*2 => 4x+6y = 154.
ii*3 => 9x+6y = 219.
5x=65; x=65/5; x=13; 26+3y=77; 3y=77-26; 3y=51; y=17.
Answer = Rs.13 and Rs.17.
3x+2y = 73 --------- ii.
---------
i*2 => 4x+6y = 154.
ii*3 => 9x+6y = 219.
5x=65; x=65/5; x=13; 26+3y=77; 3y=77-26; 3y=51; y=17.
Answer = Rs.13 and Rs.17.
Pvk said:
1 decade ago
Antony method super and correct substitute the x, y value in 1, 2 equation. Only 13, 17 satisfying.
Josh said:
1 decade ago
How do they get 26+3y?
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