Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 2)
2.
Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?
Answer: Option
Explanation:
Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city A.
Then, 2x + 3y = 77 ...(i) and
3x + 2y = 73 ...(ii)
Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.
Putting y = 17 in (i), we get: x = 13.
Discussion:
49 comments Page 3 of 5.
Bkazondarnabas said:
1 decade ago
Thank you for reminding you the formula of solving simultaneous question.
Durga said:
1 decade ago
Its very nice of getting answers by these methods.
Charan said:
1 decade ago
Why Should we multiply 2x+3y = 77 with 3 and the second one with 2?
Can anyone explain?
Can anyone explain?
Amit jain said:
10 years ago
Here,
Let the fares for city A to B = x.
Let the fares for city A to C = y.
In 1st condition.
2x+3y = 77....(i).
In 2nd condition.
3x+2y = 73....(ii).
Multiply equation (i) by 3 & equation (ii) by 2.
6x+9y = 231....(iii).
6x+4y = 146....(iv).
Subtract (iii) from (iv).
5y = 85.
Y = 17.
Put the value of why in equation (i).
2x = 77-51.
x = 13.
So,
Fares for the city A to B = x = 13.
Fares for the city A to C = y = 17.
Let the fares for city A to B = x.
Let the fares for city A to C = y.
In 1st condition.
2x+3y = 77....(i).
In 2nd condition.
3x+2y = 73....(ii).
Multiply equation (i) by 3 & equation (ii) by 2.
6x+9y = 231....(iii).
6x+4y = 146....(iv).
Subtract (iii) from (iv).
5y = 85.
Y = 17.
Put the value of why in equation (i).
2x = 77-51.
x = 13.
So,
Fares for the city A to B = x = 13.
Fares for the city A to C = y = 17.
Rashed said:
9 years ago
Hi, I'm not much good in maths but can anybody tell me how we are multiplying these equations with 3 and 2? Where these 3 and 2 comes from?
Rashid said:
9 years ago
Can anybody explain to me why we are multiplying I and ii equations with 3 and 2 respectively? Where these 3 and 2 comes from.
Ianz said:
9 years ago
Its great, by just comparing and sharing knowledge we can learn lot.
Russ said:
9 years ago
I don't understand how you got 2 and 3? Where does the 2 and 3 come in place? Please explain it.
Vivek said:
9 years ago
We do for same term of both equation.
Srinath said:
9 years ago
2X + 3Y = 77 ------> 1
3X + 2Y = 73 ------> 2
1.multiply with 3.
2.multiply with 2.
6X + 9Y = 231 ------> 3
6X + 6Y = 146 ------> 4
Subtract 3 & 4.
6X + 9Y = 231
6X + 6Y = 146
-----------------------
0 + 5y = 85
y = 85/5
y = 17.
Put y value in 1 or 2.
2X + 3(17) = 77,
2X + 51 = 77,
2X = 77 - 51 = 26.
X = 26/2 = 13.
X = 13 and Y = 17.
3X + 2Y = 73 ------> 2
1.multiply with 3.
2.multiply with 2.
6X + 9Y = 231 ------> 3
6X + 6Y = 146 ------> 4
Subtract 3 & 4.
6X + 9Y = 231
6X + 6Y = 146
-----------------------
0 + 5y = 85
y = 85/5
y = 17.
Put y value in 1 or 2.
2X + 3(17) = 77,
2X + 51 = 77,
2X = 77 - 51 = 26.
X = 26/2 = 13.
X = 13 and Y = 17.
(3)
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