Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 2)
2.
Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?
Answer: Option
Explanation:
Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city A.
Then, 2x + 3y = 77 ...(i) and
3x + 2y = 73 ...(ii)
Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.
Putting y = 17 in (i), we get: x = 13.
Discussion:
50 comments Page 5 of 5.
Sajid khan said:
1 decade ago
2x + 3y = 77.
3x + 2y = 73.
Solution :
2x + 3y = 77 (i)multiplying by 3.
6x + 9y = 231.
3x + 2y = 73 (ii)multiplying by 2.
6x + 4y = 146.
Now subtract its,
6x + 9y = 231.
6x - 4y = -146.
0x + 5y = 85.
5y = 85.
y = 85/5.
Ans y = 17.
Now put y value on the equation (i).
6x + 9(17) = 231.
6x + 153 = 231.
6x + 153 - 231 = 0.
6x - 78 = 0.
x = 78/6.
x = 13.
Solution set is { 13 , 17 }.
3x + 2y = 73.
Solution :
2x + 3y = 77 (i)multiplying by 3.
6x + 9y = 231.
3x + 2y = 73 (ii)multiplying by 2.
6x + 4y = 146.
Now subtract its,
6x + 9y = 231.
6x - 4y = -146.
0x + 5y = 85.
5y = 85.
y = 85/5.
Ans y = 17.
Now put y value on the equation (i).
6x + 9(17) = 231.
6x + 153 = 231.
6x + 153 - 231 = 0.
6x - 78 = 0.
x = 78/6.
x = 13.
Solution set is { 13 , 17 }.
Aneri Desai said:
1 decade ago
s2b(2) & s2a(3) = 77.
s2b(3) & s2a(2) = 73.
s2b=x=? & s2a=y=?
4x+6y = 154.
9x+6y = 219.
-5x = -65.
x = 13.
y = 17.
s2b(3) & s2a(2) = 73.
s2b=x=? & s2a=y=?
4x+6y = 154.
9x+6y = 219.
-5x = -65.
x = 13.
y = 17.
Reghu R said:
1 decade ago
2x+3y = 77 --------- i.
3x+2y = 73 --------- ii.
---------
i*2 => 4x+6y = 154.
ii*3 => 9x+6y = 219.
5x=65; x=65/5; x=13; 26+3y=77; 3y=77-26; 3y=51; y=17.
Answer = Rs.13 and Rs.17.
3x+2y = 73 --------- ii.
---------
i*2 => 4x+6y = 154.
ii*3 => 9x+6y = 219.
5x=65; x=65/5; x=13; 26+3y=77; 3y=77-26; 3y=51; y=17.
Answer = Rs.13 and Rs.17.
Pvk said:
1 decade ago
Antony method super and correct substitute the x, y value in 1, 2 equation. Only 13, 17 satisfying.
Josh said:
1 decade ago
How do they get 26+3y?
Bkazondarnabas said:
1 decade ago
Thank you for reminding you the formula of solving simultaneous question.
Durga said:
1 decade ago
Its very nice of getting answers by these methods.
Charan said:
1 decade ago
Why Should we multiply 2x+3y = 77 with 3 and the second one with 2?
Can anyone explain?
Can anyone explain?
Amit jain said:
1 decade ago
Here,
Let the fares for city A to B = x.
Let the fares for city A to C = y.
In 1st condition.
2x+3y = 77....(i).
In 2nd condition.
3x+2y = 73....(ii).
Multiply equation (i) by 3 & equation (ii) by 2.
6x+9y = 231....(iii).
6x+4y = 146....(iv).
Subtract (iii) from (iv).
5y = 85.
Y = 17.
Put the value of why in equation (i).
2x = 77-51.
x = 13.
So,
Fares for the city A to B = x = 13.
Fares for the city A to C = y = 17.
Let the fares for city A to B = x.
Let the fares for city A to C = y.
In 1st condition.
2x+3y = 77....(i).
In 2nd condition.
3x+2y = 73....(ii).
Multiply equation (i) by 3 & equation (ii) by 2.
6x+9y = 231....(iii).
6x+4y = 146....(iv).
Subtract (iii) from (iv).
5y = 85.
Y = 17.
Put the value of why in equation (i).
2x = 77-51.
x = 13.
So,
Fares for the city A to B = x = 13.
Fares for the city A to C = y = 17.
Rashid said:
10 years ago
Can anybody explain to me why we are multiplying I and ii equations with 3 and 2 respectively? Where these 3 and 2 comes from.
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