Mechanical Engineering - Thermodynamics - Discussion

The mass of carbon, contained in 1 kg of flue or exhaust gases, may be calculated from the mass of carbon dioxide and carbon monoxide present in them.

We know that 1 kg of carbon produces 11 / 3 kg of carbon dioxide. Hence 1 kg of carbon dioxide will contain 3 / 11 kg of carbon. Also, 1 kg of carbon produces 7/3 kg of carbon monoxide, hence 1 kg of carbon monoxide will contain 3/7 kg of carbon.

Mass of carbon per kg of flue gas is given by:
3/11 CO2+ 3/7 CO.

CO2 + CO = C.

C = 12, O2 = 32, O = 16,
CO2 = 32 + 12 = 44,
CO = 12 + 16 = 28,
CO2 + CO = C,
44 kg + 28 kg =12 kg,
44/12 kg + 28/12 =1 kg carbon,
11/3 kg + 7/3 kg = 1 kg carbon.

I think it's 3/11 CO2, 3/7 CO.

Mass of carbon per kg of flue gas is given by:
3/11 CO2 + 3/7 CO.

I agree with @Mr. VelmuruganR. You are perfectly explained.

We know that one kg of carbon produced 11/3 kg of CO2 and 7/3 kg of CO.

So per kg of this gaseous, carbon will be produced 3/11 kg of CO2 and 3/7 kg of CO.

So, according to me, no any answer is correct in above mention option.

I think the answer would be 3/11CO2 + 3/7CO.

Yes, right @Syed Sameer.

The mass of carbon, contained in 1 kg of flue or exhaust gases, may be calculated from the mass of carbon dioxide and carbon monoxide present in them.

We know that 1 kg of carbon produces 11/3 kg of carbon dioxide. Hence 1 kg of carbon dioxide will contain 3/11 kg of carbon. Also, 1 kg of carbon produces 7/3 kg of carbon monoxide, hence 1 kg of carbon monoxide will contain 3/7 kg of carbon.

Mass of carbon per kg of flue gas is given by:
3/11CO2 + 3/7CO.

@Biplab.

CO2 + CO = C is not balanced.
I think Balanced equation is CO2+2CO=3C+2O2.