Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 1 (Q.No. 16)
16.
The most probable velocity of the gas molecules is given by
Discussion:
33 comments Page 1 of 4.
Engr. Amir Shehzad said:
3 years ago
K.E is directly proportional to Temperature.
1/2mv^2 = kT.
v^2 = 2kT/m.
So v=√(2kT/m).
Where k= proportionality constant.
1/2mv^2 = kT.
v^2 = 2kT/m.
So v=√(2kT/m).
Where k= proportionality constant.
(15)
Vinay said:
5 years ago
Option B is right.
Kanisetti saikumar said:
5 years ago
Most probable velocity of gas molecules = √2kt/m.
Thamarai said:
5 years ago
Can anyone explain option A and D?
Raj Singh said:
6 years ago
Why is R used instead of k in mp velocity sometimes?
Sadam said:
6 years ago
Can anyone explain option B?
Anil said:
7 years ago
I it B or C? Please explain.
Naveen singh said:
8 years ago
B is right. C is vrms.
(2)
Sathish said:
8 years ago
Please explain about this.
Rajesh rank said:
8 years ago
Answer B. Probable velocity of the gas molecules.
Answer C. Typical velocity of molecules in a gas.
In the question, they asked probable velocity so Answer B is right.
Answer C. Typical velocity of molecules in a gas.
In the question, they asked probable velocity so Answer B is right.
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