Mechanical Engineering - Industrial Engineering and Production Management - Discussion

Discussion Forum : Industrial Engineering and Production Management - Section 1 (Q.No. 15)
15.
In a network shown in the below figure, the critical path is along
1-2-3-4-8-9
1-2-3-5-6-7-8-9
1-2-3-4-7-8-9
1-2-5-6-7-8-9
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
32 comments Page 1 of 4.

Bhaskar said:   1 year ago
Agree, the right answer is B.

Vignesh reddy said:   3 years ago
@All
Option -A is correct because a dummy is said to be critical.

EST =LST.

So, there is no chance.

Sukarma said:   4 years ago
How to find the dummy activity? Anyone explain it.

Aniket said:   4 years ago
A dummy activity can be either critical or non-critical. It becomes a critical activity when the earlier start time and the latest finish time are equal.

Vanraj Gajarotar said:   5 years ago
Option B is the right answer.

Zeeshan_Pak said:   5 years ago
A dummy activity can only become critical when its EST is the same as its LFT.
That's why D2 is considered critical and D1 is not.
So, Option B is right.

S V Manikandan. said:   5 years ago
Critical path is one, which consumes more time to complete. By this way, I can choose option B. The dummy loop is unaccountable.

Sagar Chavan said:   5 years ago
Option A is correct.
(1)

Karthi said:   6 years ago
The critical path consist of the longest path duration 1-2-3-5-6-7-8-9 is 24 units.

Vetan said:   6 years ago
The critical path has the longest path and consumes maximum time and maximum resource
So option B is correct.

1-2-3-5-6-7-8-9 = 24.


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