Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion

Discussion Forum : Hydraulics and Fluid Mechanics - Section 2 (Q.No. 15)
15.
A water tank contains 1.3 m deep water. The pressure exerted by the water per metre length of the tank is
2.89 kN
8.29 kN
9.28 kN
28.9 kN
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
25 comments Page 1 of 3.

YATHEESH KUMAR D B said:   2 years ago
Let's consider a triangle and it has a height of 1.3 m and the pressure occurring at its bottom is p = 1.3 * 9.81 * 1000 = 12.753kPa.
Then, the triangle can be written as = 0.5 * B * H.
=0.5 * 12.753 * 1.3.
= 8.289kN/m.
(2)

Abhishek said:   4 years ago
pressure exerted per unit length = ωH2/2.
= (9. 81x103x1.32)/2.
= 8.29 KN.
(1)

Sushil Dumka said:   8 years ago
Yes, the answer is right,
8.29 kN.
Pressure diagram becomes triangular and area of triangular is 1/2 wh^2.
(1)

Jsh said:   8 years ago
Pressure =density *gravity *cg of projected area.
Cg lies at half of height.
Force = pressure * area.
Area = height * length.
Force =ρg(h/2)*h*l.
F=8.2.
(1)

Arun kumar said:   8 years ago
P=ρgh^2/2
ρ=1000
g=9.81
h=1.3
Than put,

P=1000*9.81*1.3*1.3/2=8289.45N=8.289KN.
(1)

Ram said:   8 years ago
Thank you all for the explanation.

Mohammad Zubair Khan said:   5 years ago
10^3 or 1000 being multiplied to convert the unit from N (Newton) to KN (Kilo Newton).

NILADRI NAG said:   5 years ago
Why 1000 is being multiplied with the equation? Anyone explain.

Anomie said:   7 years ago
@All.

The pressure cannot have the unit kiloNewton. And the Pressure can only be exerted on an area there is nothing called as the pressure exerted on a unit length.

Rakshit Khatri said:   7 years ago
@Aman Kumar.

The pressure exerted by the water per metre length of the tank.


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