### Discussion :: Hydraulics and Fluid Mechanics - Section 2 (Q.No.15)

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Suman Biswas said: (Jul 8, 2013) | |

We know pressure exerted per unit length = ωH^{2}/2.So, the pressure of water per metre length = (9. 81x10 ^{3}x1.3^{2}) /2.= 8.29 KN. |

Prateek said: (Sep 2, 2016) | |

Absolutely right @Suman. |

Hema said: (Sep 12, 2016) | |

Can anyone explain how that equation comes? |

Hartoon said: (Oct 19, 2016) | |

@Hema, please refer the book. |

Ravindra said: (Nov 17, 2016) | |

Pressure diagram is triangular. Base is equal to wh and height h so pressure becomes 1/2 base * height. So pressure becomes wh*h/2. |

Amit said: (Feb 12, 2017) | |

Thanks for giving the correct explanation. |

Vinayak said: (Mar 2, 2017) | |

Thank you for giving the solution. |

Manish Kumar said: (Mar 4, 2017) | |

We know that, pressure= £gh ,where £= density. Now, pressure exerted by the water (force) = pressure* area = £gh* wh/2 (pre dia is triangular =(1/2)*base*h), So, pressure exerted per unit lenght(pressure/w) = £gh* h/2 = (1000*9.81*1.3*1.3)/2 = 8.29 kN. |

Gupta said: (May 31, 2017) | |

Thanks for the explanation. |

Narpat said: (Jun 12, 2017) | |

Here, w = &rho * g. |

Vaibhav said: (Jun 13, 2017) | |

Can anyone explain me how that area came? |

Vikaah Choudhary said: (Jun 16, 2017) | |

Good explanation, thanks @Suman. |

Ram said: (Aug 15, 2017) | |

Thank you all for the explanation. |

Waseem Iqbal said: (Aug 21, 2017) | |

Hydraulic force P= rAh'. Where h' = depth of center of gravity = h/2 in this case. So P = r (L*h) h/2 = 9.81 * (1.3)^2 /2. ( L cancel out for per meter length). |

Arun Kumar said: (Sep 14, 2017) | |

P=ρgh^2/2 ρ=1000 g=9.81 h=1.3 Than put, P=1000*9.81*1.3*1.3/2=8289.45N=8.289KN. |

Naresh said: (Oct 3, 2017) | |

Yes right @Arun Kumar. Here it is not mentioned that tank is a triangular or rectangular or as square tank. so the pressure at a particular point is given by p=wh^2/2 and density of water is given by pgh. |

Jsh said: (Oct 20, 2017) | |

Pressure =density *gravity *cg of projected area. Cg lies at half of height. Force = pressure * area. Area = height * length. Force =ρg(h/2)*h*l. F=8.2. |

Sushil Dumka said: (Feb 27, 2018) | |

Yes, the answer is right, 8.29 kN. Pressure diagram becomes triangular and area of triangular is 1/2 wh^2. |

Aman Kumar said: (Apr 3, 2018) | |

Is it pressure exerted per unit length or pressure force exerted per unit length? Please tell me. |

Rakshit Khatri said: (Oct 27, 2018) | |

@Aman Kumar. The pressure exerted by the water per metre length of the tank. |

Anomie said: (Feb 2, 2019) | |

@All. The pressure cannot have the unit kiloNewton. And the Pressure can only be exerted on an area there is nothing called as the pressure exerted on a unit length. |

Niladri Nag said: (Sep 4, 2020) | |

Why 1000 is being multiplied with the equation? Anyone explain. |

Mohammad Zubair Khan said: (Jan 19, 2021) | |

10^3 or 1000 being multiplied to convert the unit from N (Newton) to KN (Kilo Newton). |

Abhishek said: (Jul 20, 2021) | |

pressure exerted per unit length = ωH2/2. = (9. 81x103x1.32)/2. = 8.29 KN. |

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