Discussion :: Hydraulics and Fluid Mechanics - Section 2 (Q.No.15)
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A water tank contains 1.3 m deep water. The pressure exerted by the water per metre length of the tank is
Answer: Option B
No answer description available for this question.
|Suman Biswas said: (Jul 8, 2013)|
|We know pressure exerted per unit length = ωH2/2.
So, the pressure of water per metre length = (9. 81x103x1.32) /2.
= 8.29 KN.
|Prateek said: (Sep 2, 2016)|
|Absolutely right @Suman.|
|Hema said: (Sep 12, 2016)|
|Can anyone explain how that equation comes?|
|Hartoon said: (Oct 19, 2016)|
|@Hema, please refer the book.|
|Ravindra said: (Nov 17, 2016)|
|Pressure diagram is triangular. Base is equal to wh and height h so pressure becomes 1/2 base * height. So pressure becomes wh*h/2.|
|Amit said: (Feb 12, 2017)|
|Thanks for giving the correct explanation.|
|Vinayak said: (Mar 2, 2017)|
|Thank you for giving the solution.|
|Manish Kumar said: (Mar 4, 2017)|
|We know that, pressure= £gh ,where £= density.
Now, pressure exerted by the water (force) = pressure* area = £gh* wh/2 (pre dia is triangular =(1/2)*base*h),
So, pressure exerted per unit lenght(pressure/w) = £gh* h/2 = (1000*9.81*1.3*1.3)/2 = 8.29 kN.
|Gupta said: (May 31, 2017)|
|Thanks for the explanation.|
|Narpat said: (Jun 12, 2017)|
|Here, w = &rho * g.|
|Vaibhav said: (Jun 13, 2017)|
|Can anyone explain me how that area came?|
|Vikaah Choudhary said: (Jun 16, 2017)|
|Good explanation, thanks @Suman.|
|Ram said: (Aug 15, 2017)|
|Thank you all for the explanation.|
|Waseem Iqbal said: (Aug 21, 2017)|
|Hydraulic force P= rAh'.
Where h' = depth of center of gravity = h/2 in this case.
So P = r (L*h) h/2 = 9.81 * (1.3)^2 /2. ( L cancel out for per meter length).
|Arun Kumar said: (Sep 14, 2017)|
|Naresh said: (Oct 3, 2017)|
|Yes right @Arun Kumar.
Here it is not mentioned that tank is a triangular or rectangular or as square tank.
so the pressure at a particular point is given by p=wh^2/2 and density of water is given by pgh.
|Jsh said: (Oct 20, 2017)|
|Pressure =density *gravity *cg of projected area.
Cg lies at half of height.
Force = pressure * area.
Area = height * length.
|Sushil Dumka said: (Feb 27, 2018)|
|Yes, the answer is right,
Pressure diagram becomes triangular and area of triangular is 1/2 wh^2.
|Aman Kumar said: (Apr 3, 2018)|
|Is it pressure exerted per unit length or pressure force exerted per unit length? Please tell me.|
|Rakshit Khatri said: (Oct 27, 2018)|
The pressure exerted by the water per metre length of the tank.
|Anomie said: (Feb 2, 2019)|
The pressure cannot have the unit kiloNewton. And the Pressure can only be exerted on an area there is nothing called as the pressure exerted on a unit length.
|Niladri Nag said: (Sep 4, 2020)|
|Why 1000 is being multiplied with the equation? Anyone explain.|
|Mohammad Zubair Khan said: (Jan 19, 2021)|
|10^3 or 1000 being multiplied to convert the unit from N (Newton) to KN (Kilo Newton).|
|Abhishek said: (Jul 20, 2021)|
|pressure exerted per unit length = ωH2/2.
= (9. 81x103x1.32)/2.
= 8.29 KN.
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