# Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion

15.

A water tank contains 1.3 m deep water. The pressure exerted by the water per metre length of the tank is

 [A]. 2.89 kN [B]. 8.29 kN [C]. 9.28 kN [D]. 28.9 kN

Explanation:

No answer description available for this question.

 Suman Biswas said: (Jul 8, 2013) We know pressure exerted per unit length = ωH2/2. So, the pressure of water per metre length = (9. 81x103x1.32) /2. = 8.29 KN.

 Prateek said: (Sep 2, 2016) Absolutely right @Suman.

 Hema said: (Sep 12, 2016) Can anyone explain how that equation comes?

 Hartoon said: (Oct 19, 2016) @Hema, please refer the book.

 Ravindra said: (Nov 17, 2016) Pressure diagram is triangular. Base is equal to wh and height h so pressure becomes 1/2 base * height. So pressure becomes wh*h/2.

 Amit said: (Feb 12, 2017) Thanks for giving the correct explanation.

 Vinayak said: (Mar 2, 2017) Thank you for giving the solution.

 Manish Kumar said: (Mar 4, 2017) We know that, pressure= £gh ,where £= density. Now, pressure exerted by the water (force) = pressure* area = £gh* wh/2 (pre dia is triangular =(1/2)*base*h), So, pressure exerted per unit lenght(pressure/w) = £gh* h/2 = (1000*9.81*1.3*1.3)/2 = 8.29 kN.

 Gupta said: (May 31, 2017) Thanks for the explanation.

 Narpat said: (Jun 12, 2017) Here, w = &rho * g.

 Vaibhav said: (Jun 13, 2017) Can anyone explain me how that area came?

 Vikaah Choudhary said: (Jun 16, 2017) Good explanation, thanks @Suman.

 Ram said: (Aug 15, 2017) Thank you all for the explanation.

 Waseem Iqbal said: (Aug 21, 2017) Hydraulic force P= rAh'. Where h' = depth of center of gravity = h/2 in this case. So P = r (L*h) h/2 = 9.81 * (1.3)^2 /2. ( L cancel out for per meter length).

 Arun Kumar said: (Sep 14, 2017) P=ρgh^2/2 ρ=1000 g=9.81 h=1.3 Than put, P=1000*9.81*1.3*1.3/2=8289.45N=8.289KN.

 Naresh said: (Oct 3, 2017) Yes right @Arun Kumar. Here it is not mentioned that tank is a triangular or rectangular or as square tank. so the pressure at a particular point is given by p=wh^2/2 and density of water is given by pgh.

 Jsh said: (Oct 20, 2017) Pressure =density *gravity *cg of projected area. Cg lies at half of height. Force = pressure * area. Area = height * length. Force =ρg(h/2)*h*l. F=8.2.

 Sushil Dumka said: (Feb 27, 2018) Yes, the answer is right, 8.29 kN. Pressure diagram becomes triangular and area of triangular is 1/2 wh^2.

 Aman Kumar said: (Apr 3, 2018) Is it pressure exerted per unit length or pressure force exerted per unit length? Please tell me.

 Rakshit Khatri said: (Oct 27, 2018) @Aman Kumar. The pressure exerted by the water per metre length of the tank.

 Anomie said: (Feb 2, 2019) @All. The pressure cannot have the unit kiloNewton. And the Pressure can only be exerted on an area there is nothing called as the pressure exerted on a unit length.

 Niladri Nag said: (Sep 4, 2020) Why 1000 is being multiplied with the equation? Anyone explain.

 Mohammad Zubair Khan said: (Jan 19, 2021) 10^3 or 1000 being multiplied to convert the unit from N (Newton) to KN (Kilo Newton).

 Abhishek said: (Jul 20, 2021) pressure exerted per unit length = ωH2/2. = (9. 81x103x1.32)/2. = 8.29 KN.