Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 2 (Q.No. 15)
15.
A water tank contains 1.3 m deep water. The pressure exerted by the water per metre length of the tank is
Discussion:
25 comments Page 1 of 3.
SUMAN BISWAS said:
1 decade ago
We know pressure exerted per unit length = ωH2/2.
So, the pressure of water per metre length = (9. 81x103x1.32) /2.
= 8.29 KN.
So, the pressure of water per metre length = (9. 81x103x1.32) /2.
= 8.29 KN.
Prateek said:
9 years ago
Absolutely right @Suman.
Hema said:
9 years ago
Can anyone explain how that equation comes?
Hartoon said:
9 years ago
@Hema, please refer the book.
Ravindra said:
9 years ago
Pressure diagram is triangular. Base is equal to wh and height h so pressure becomes 1/2 base * height. So pressure becomes wh*h/2.
Amit said:
9 years ago
Thanks for giving the correct explanation.
Vinayak said:
9 years ago
Thank you for giving the solution.
Manish kumar said:
9 years ago
We know that, pressure= £gh ,where £= density.
Now, pressure exerted by the water (force) = pressure* area = £gh* wh/2 (pre dia is triangular =(1/2)*base*h),
So, pressure exerted per unit lenght(pressure/w) = £gh* h/2 = (1000*9.81*1.3*1.3)/2 = 8.29 kN.
Now, pressure exerted by the water (force) = pressure* area = £gh* wh/2 (pre dia is triangular =(1/2)*base*h),
So, pressure exerted per unit lenght(pressure/w) = £gh* h/2 = (1000*9.81*1.3*1.3)/2 = 8.29 kN.
Gupta said:
8 years ago
Thanks for the explanation.
Narpat said:
8 years ago
Here, w = &rho * g.
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