Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion

Discussion Forum : Hydraulics and Fluid Mechanics - Section 2 (Q.No. 15)
15.
A water tank contains 1.3 m deep water. The pressure exerted by the water per metre length of the tank is
2.89 kN
8.29 kN
9.28 kN
28.9 kN
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
25 comments Page 2 of 3.

Vaibhav said:   8 years ago
Can anyone explain me how that area came?

Vikaah Choudhary said:   8 years ago
Good explanation, thanks @Suman.

Ram said:   8 years ago
Thank you all for the explanation.

Waseem iqbal said:   8 years ago
Hydraulic force P= rAh'.

Where h' = depth of center of gravity = h/2 in this case.

So P = r (L*h) h/2 = 9.81 * (1.3)^2 /2. ( L cancel out for per meter length).

Arun kumar said:   8 years ago
P=ρgh^2/2
ρ=1000
g=9.81
h=1.3
Than put,

P=1000*9.81*1.3*1.3/2=8289.45N=8.289KN.
(1)

Naresh said:   8 years ago
Yes right @Arun Kumar.

Here it is not mentioned that tank is a triangular or rectangular or as square tank.

so the pressure at a particular point is given by p=wh^2/2 and density of water is given by pgh.

Jsh said:   8 years ago
Pressure =density *gravity *cg of projected area.
Cg lies at half of height.
Force = pressure * area.
Area = height * length.
Force =ρg(h/2)*h*l.
F=8.2.
(1)

Sushil Dumka said:   8 years ago
Yes, the answer is right,
8.29 kN.
Pressure diagram becomes triangular and area of triangular is 1/2 wh^2.
(1)

Aman kumar said:   8 years ago
Is it pressure exerted per unit length or pressure force exerted per unit length? Please tell me.

Rakshit Khatri said:   7 years ago
@Aman Kumar.

The pressure exerted by the water per metre length of the tank.


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