Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion

Discussion Forum : Hydraulics and Fluid Mechanics - Section 2 (Q.No. 15)
15.
A water tank contains 1.3 m deep water. The pressure exerted by the water per metre length of the tank is
2.89 kN
8.29 kN
9.28 kN
28.9 kN
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
25 comments Page 2 of 3.

Aman kumar said:   8 years ago
Is it pressure exerted per unit length or pressure force exerted per unit length? Please tell me.

Naresh said:   8 years ago
Yes right @Arun Kumar.

Here it is not mentioned that tank is a triangular or rectangular or as square tank.

so the pressure at a particular point is given by p=wh^2/2 and density of water is given by pgh.

Waseem iqbal said:   8 years ago
Hydraulic force P= rAh'.

Where h' = depth of center of gravity = h/2 in this case.

So P = r (L*h) h/2 = 9.81 * (1.3)^2 /2. ( L cancel out for per meter length).

SUMAN BISWAS said:   1 decade ago
We know pressure exerted per unit length = ωH2/2.

So, the pressure of water per metre length = (9. 81x103x1.32) /2.

= 8.29 KN.

Vikaah Choudhary said:   8 years ago
Good explanation, thanks @Suman.

Narpat said:   8 years ago
Here, w = &rho * g.

Vaibhav said:   8 years ago
Can anyone explain me how that area came?

Gupta said:   8 years ago
Thanks for the explanation.

Manish kumar said:   9 years ago
We know that, pressure= £gh ,where £= density.
Now, pressure exerted by the water (force) = pressure* area = £gh* wh/2 (pre dia is triangular =(1/2)*base*h),

So, pressure exerted per unit lenght(pressure/w) = £gh* h/2 = (1000*9.81*1.3*1.3)/2 = 8.29 kN.

Vinayak said:   9 years ago
Thank you for giving the solution.


Post your comments here:

Your comments will be displayed after verification.