Mechanical Engineering - Heat Transfer, Refrigeration and Air Conditioning - Discussion
Discussion Forum : Heat Transfer, Refrigeration and Air Conditioning - Section 6 (Q.No. 1)
1.
A condenser of refrigeration system rejects heat at the rate of 120 kW, while its compressor consumes a power of 30 kW. The coefficient of performance of the system will be
Discussion:
26 comments Page 1 of 3.
Gaurav said:
1 decade ago
C.O.P = favourable effect/work input = 120/30 = 4.
Here favourable effect is rejection of heat.
Here favourable effect is rejection of heat.
Indra bhushan rai said:
1 decade ago
Refrigeration effect = 120-30 = 90.
cop = 90/30 = 3.
cop = 90/30 = 3.
Ankusb said:
9 years ago
I agree with you @Indra 3 is the correct answer.
Jignesh said:
9 years ago
cop = R.E/WORK = 90/30 = 3.
Jnk said:
9 years ago
cop = ref effect / work done.
= 120 - 30 / 30.
= 3.
= 120 - 30 / 30.
= 3.
Ajith said:
9 years ago
C.O.P = heat/workdone,
=> 120/30,
=> 4.
=> 120/30,
=> 4.
Mehul J said:
9 years ago
Heat rejected = Heat taken from Evaporator + heat rejected from compressor.
Here heat Rejected is given as summation of RE+ W ( Compressor).
Now COP = RE/Work.
= 120 - 30/30 = 3.
Here heat Rejected is given as summation of RE+ W ( Compressor).
Now COP = RE/Work.
= 120 - 30/30 = 3.
Lucky Patel said:
9 years ago
Answer should be 3.
Because the ratio of condenser heat rejection to power consumption is called co efficient of performance for the heat pump. And we have to find cop of refrigerator thus from equation
COP hp =COPr + 1.
Cop for refrigerator 3.
Because the ratio of condenser heat rejection to power consumption is called co efficient of performance for the heat pump. And we have to find cop of refrigerator thus from equation
COP hp =COPr + 1.
Cop for refrigerator 3.
Rakesh thakur said:
9 years ago
cop = out put /input.
energy out /input.
120/30.
energy out /input.
120/30.
Yatendra said:
8 years ago
Yes, I agree cop = 3.
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