Mechanical Engineering - Heat Transfer, Refrigeration and Air Conditioning - Discussion
Discussion Forum : Heat Transfer, Refrigeration and Air Conditioning - Section 6 (Q.No. 1)
1.
A condenser of refrigeration system rejects heat at the rate of 120 kW, while its compressor consumes a power of 30 kW. The coefficient of performance of the system will be
Discussion:
26 comments Page 2 of 3.
Manash said:
8 years ago
The answer is (c) 3.
Anand Kumar Singh said:
8 years ago
3 is the correct answer.
Prabhat swain said:
8 years ago
This question also came in Isro exam.
And answer key of ISRo shows the correct answer is 3.
So, the answer is 3.
And answer key of ISRo shows the correct answer is 3.
So, the answer is 3.
Prabhat swain said:
8 years ago
@Rakesh Thakur.
Output/input not COP.
This is efficiency.
COP is the reciprocal of efficiency.
Output/input not COP.
This is efficiency.
COP is the reciprocal of efficiency.
Lalit Kumar said:
8 years ago
120-30 = 90.
Cop=90/30=3 => ans.
Cop=90/30=3 => ans.
Vishnu p said:
8 years ago
Answer will be 3 because here 120 is heat rejected not heat extracted.
Vishnu said:
7 years ago
The answer is 3.
Here 120 is the heat rejected to the atmosphere, not the heat absorbed from the refrigerated space.
120 - 30 is the heat absorbed from the refigerated space.
The Work input is 30.
Here 120 is the heat rejected to the atmosphere, not the heat absorbed from the refrigerated space.
120 - 30 is the heat absorbed from the refigerated space.
The Work input is 30.
Zeeshan said:
7 years ago
Point to ponder is whether the COP of the heat pump is asked or COP of the Refrigeration system. The question doesn't define the fact categorically. Assuming heat pump answer is 4, of we assume COP of refrigeration system then given answer is wrong and it must be 3.
Swagat said:
6 years ago
COP = (120-30)/30.
= 3.
= 3.
(2)
S Kamran said:
6 years ago
Answer will be 3..
120kw is heat rejected(not R.E)by the condenser that heat is the sum of Refrigeration effect(R.E)& The heat added by compressor work.. & COP= R.E/Work Input. So the final answer will be COP=(120-30)/30=3.
120kw is heat rejected(not R.E)by the condenser that heat is the sum of Refrigeration effect(R.E)& The heat added by compressor work.. & COP= R.E/Work Input. So the final answer will be COP=(120-30)/30=3.
(1)
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