Mechanical Engineering - Heat Transfer, Refrigeration and Air Conditioning - Discussion
Discussion Forum : Heat Transfer, Refrigeration and Air Conditioning - Section 6 (Q.No. 1)
1.
A condenser of refrigeration system rejects heat at the rate of 120 kW, while its compressor consumes a power of 30 kW. The coefficient of performance of the system will be
Discussion:
26 comments Page 3 of 3.
Swapnil Shelke said:
5 years ago
I also agree with the answer 3 as here COP of the refrigeration system is asked clearly here REFRIGERATING EFFECT is 90 and work input 30.
(1)
Kajal Patil said:
5 years ago
3 is the correct Answer.
(2)
Vinay BEL said:
5 years ago
120 - 30 = 90.
Cop=90/30=3 => answer.
Cop=90/30=3 => answer.
(1)
Amaan Sayyed said:
5 years ago
120/30=4 this is the right answer.
Pratheesh said:
5 years ago
The Answer should be 3.
(1)
Muluneh getnet said:
3 months ago
To calculate the coefficient of performance (COP) of a refrigeration system, we use the formula:
{COP}_ {refrigeration}} = {Q_L}{W}
Where:
QL = Refrigeration effect = heat absorbed in the evaporator (in kW)
W = Work input to the compressor (in kW)
But in your question, the condenser rejects heat at the rate of 120 kW, and the compressor consumes 30 kW of power.
We know:
QH = QL + W.
Where:
(heat rejected by the condenser)
(compressor work)
So, the refrigeration effect is:
QL = QH - W
= 120 - 30 = 90{kW}
Now calculate the COP:
{COP} = {Q_L}{W} = {90}{30} = 3
So, the Final Answer: COP = 3.
{COP}_ {refrigeration}} = {Q_L}{W}
Where:
QL = Refrigeration effect = heat absorbed in the evaporator (in kW)
W = Work input to the compressor (in kW)
But in your question, the condenser rejects heat at the rate of 120 kW, and the compressor consumes 30 kW of power.
We know:
QH = QL + W.
Where:
(heat rejected by the condenser)
(compressor work)
So, the refrigeration effect is:
QL = QH - W
= 120 - 30 = 90{kW}
Now calculate the COP:
{COP} = {Q_L}{W} = {90}{30} = 3
So, the Final Answer: COP = 3.
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