Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 50)
50.
If two bodies having masses m1 and m2 (m1>m2) have equal kinetic energies, the momentum of body having mass m1 is __________ the momentum of body having mass m2.
Discussion:
32 comments Page 4 of 4.
Ambarish said:
1 decade ago
1/2m1(v1)^2 = 1/2m2(v2)^2.
= m1(v1)^2 = m2(v2)^2.
= m1(v1)^2/m2(v2)^2 = 1.
= (v1)^2/(v2)^2 is greater than 1(science m1/m2 is greater than 1).
= v1^2is greater than v2^2.
= v1 is greater than v2.
So, m1v1 is greater than m2v2.
= m1(v1)^2 = m2(v2)^2.
= m1(v1)^2/m2(v2)^2 = 1.
= (v1)^2/(v2)^2 is greater than 1(science m1/m2 is greater than 1).
= v1^2is greater than v2^2.
= v1 is greater than v2.
So, m1v1 is greater than m2v2.
Dev said:
1 decade ago
How came m1v1 is greater?
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