Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 50)
50.
If two bodies having masses m1 and m2 (m1>m2) have equal kinetic energies, the momentum of body having mass m1 is __________ the momentum of body having mass m2.
Discussion:
32 comments Page 3 of 4.
Amit papa said:
9 years ago
(1/2)m1v1^2 = (1/2)m2v2^2 (equation showing the equal kinetic energy where m1>m2).
By cancelling (1/2) on both sides, we get,
m1v1^2 = m2v2^2.
p1v1 = p2v2 = constant (denoting p = mv which is momentum).
So, to make the product of two quantities equal, p1>p2.
Because v1
Because of m1>m2.
By cancelling (1/2) on both sides, we get,
m1v1^2 = m2v2^2.
p1v1 = p2v2 = constant (denoting p = mv which is momentum).
So, to make the product of two quantities equal, p1>p2.
Because v1
Because of m1>m2.
Dhiru said:
10 years ago
K.E-p^2/2m.
p - Momentum.
p - Momentum.
Johny said:
10 years ago
KE1 = KE2.
= 1/2M1V1^2 = 1/2M2V2^2.
= M1>M2.
= V2^2>V1^2 but V2/V1 lesser than V2^2/V1^2.
Or we say V2/V1 lesser than M1/M2 also.
So M1V1>M2V2.
= 1/2M1V1^2 = 1/2M2V2^2.
= M1>M2.
= V2^2>V1^2 but V2/V1 lesser than V2^2/V1^2.
Or we say V2/V1 lesser than M1/M2 also.
So M1V1>M2V2.
Seshu said:
10 years ago
We know that KE = 1/2mv^2. If m value increases moment increases.
So body 1 mass is higher than body 2. So momentum of body 1 greater than body 2.
So body 1 mass is higher than body 2. So momentum of body 1 greater than body 2.
Nitin said:
10 years ago
@Sashi.
But don't forget momentum also depends upon velocity and you missed that.
But don't forget momentum also depends upon velocity and you missed that.
Sandy said:
10 years ago
Since Momentum = Mass Acceleration.
That means Momentum is directly proportional to the mass.
So, if mass is more the momentum will also be more.
That means Momentum is directly proportional to the mass.
So, if mass is more the momentum will also be more.
Sasi said:
1 decade ago
Momentum = Mass*Velocity.
Here (mass) m1>m2.
Hence momentum of body 1 is greater than the body 2.
Here (mass) m1>m2.
Hence momentum of body 1 is greater than the body 2.
Sasi said:
1 decade ago
Momentum = Mass*Velocity.
Here (mass) m1>m2.
Hence momentum of body 1 is greater than the body 2.
Here (mass) m1>m2.
Hence momentum of body 1 is greater than the body 2.
Kingshuk said:
1 decade ago
@Harish.
You are wrong. Velocities can not be equal in order to attain equal K. E where m1>m2.
You are wrong. Velocities can not be equal in order to attain equal K. E where m1>m2.
Gaurav said:
1 decade ago
Consider m1 = 4, v1 = 2, m2 = 1, v2 = 4.
Here m1v1>m2v2 :).
Here m1v1>m2v2 :).
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