Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 50)
50.
If two bodies having masses m1 and m2 (m1>m2) have equal kinetic energies, the momentum of body having mass m1 is __________ the momentum of body having mass m2.
Discussion:
33 comments Page 1 of 4.
Pratyay said:
7 years ago
IF m<M & v,V are their velocity respectively.
1/2(mv^2)=1/2(MV^2).
m.v*v=M.V*V.
if m<M,in order to get same K.E, v>V.
Now,
p.v=P.V (p=m.v & P=M.V).
as v>V, in order to get same K.E,
So, P>p.
1/2(mv^2)=1/2(MV^2).
m.v*v=M.V*V.
if m<M,in order to get same K.E, v>V.
Now,
p.v=P.V (p=m.v & P=M.V).
as v>V, in order to get same K.E,
So, P>p.
(2)
Gaurav said:
6 months ago
Thanks all.
(1)
Hassan rizwi said:
8 years ago
Simple greater the mass greater the momentum.
(1)
Mechoy said:
6 years ago
Simply.
Momentum is related to mass and velocity.
If mass and velocity increase then momentum will increase.
So finally, m1>m2.
Momentum is related to mass and velocity.
If mass and velocity increase then momentum will increase.
So finally, m1>m2.
(1)
Ajay Dubile said:
2 years ago
Good, thanks all.
(1)
Harish said:
1 decade ago
@Suresh.
Given, K.E1 = K.E2, also m1>m2, K.E1 = 1/2m1v1^2, K.E2 = 1/2m2v2^2.
In order to get both the KE equal, their Velocity should be equal since m1>m2 (given). Therefore, Momentum, m1v1 > m2v2.
Given, K.E1 = K.E2, also m1>m2, K.E1 = 1/2m1v1^2, K.E2 = 1/2m2v2^2.
In order to get both the KE equal, their Velocity should be equal since m1>m2 (given). Therefore, Momentum, m1v1 > m2v2.
(1)
Deep said:
1 decade ago
1/2 m1 v1^2 = 1/2 m2 v2^2.
As m1>m2 So v2 must be >v1.
m1.v1/m2.v2=v2/v1 will have value greater than 1. So m1.v1>m2.v2.
As m1>m2 So v2 must be >v1.
m1.v1/m2.v2=v2/v1 will have value greater than 1. So m1.v1>m2.v2.
(1)
Suresh kumawat said:
1 decade ago
How can you say that v1 = v2.
(1)
Mohsin Ali said:
4 years ago
You are absolutely right @Johny.
Kamran Ashraf said:
5 years ago
Ke1 = ke2,
m1v1^2 = m2v2^2,
m1v1 * v1 = m2v2 * v2,
Moment1 *v1 = Moment2 *v2,
Moment1/Moment2 = v2/v1.
m1>m2 so for equal KE v2>v1 i.e v2/v1 >1;
Moment1>Moment2.
m1v1^2 = m2v2^2,
m1v1 * v1 = m2v2 * v2,
Moment1 *v1 = Moment2 *v2,
Moment1/Moment2 = v2/v1.
m1>m2 so for equal KE v2>v1 i.e v2/v1 >1;
Moment1>Moment2.
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