Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 50)
50.
If two bodies having masses m1 and m2 (m1>m2) have equal kinetic energies, the momentum of body having mass m1 is __________ the momentum of body having mass m2.
Discussion:
32 comments Page 1 of 4.
Ajay Dubile said:
10 months ago
Good, thanks all.
Mohsin Ali said:
3 years ago
You are absolutely right @Johny.
Kamran Ashraf said:
4 years ago
Ke1 = ke2,
m1v1^2 = m2v2^2,
m1v1 * v1 = m2v2 * v2,
Moment1 *v1 = Moment2 *v2,
Moment1/Moment2 = v2/v1.
m1>m2 so for equal KE v2>v1 i.e v2/v1 >1;
Moment1>Moment2.
m1v1^2 = m2v2^2,
m1v1 * v1 = m2v2 * v2,
Moment1 *v1 = Moment2 *v2,
Moment1/Moment2 = v2/v1.
m1>m2 so for equal KE v2>v1 i.e v2/v1 >1;
Moment1>Moment2.
Vishnu said:
5 years ago
V1 can't be equal to v2 as if they were equal how come kinetic energy be equal as mass are different? Explain please.
Mechoy said:
5 years ago
Simply.
Momentum is related to mass and velocity.
If mass and velocity increase then momentum will increase.
So finally, m1>m2.
Momentum is related to mass and velocity.
If mass and velocity increase then momentum will increase.
So finally, m1>m2.
(1)
Satya Jeet Verma said:
6 years ago
K.E= p^2/2*m.
KE1=KE2.
P1^2/2*m1=P2^/2*m2.
since m1>m2.
So P1>P2.
KE1=KE2.
P1^2/2*m1=P2^/2*m2.
since m1>m2.
So P1>P2.
Pratyay said:
6 years ago
IF m<M & v,V are their velocity respectively.
1/2(mv^2)=1/2(MV^2).
m.v*v=M.V*V.
if m<M,in order to get same K.E, v>V.
Now,
p.v=P.V (p=m.v & P=M.V).
as v>V, in order to get same K.E,
So, P>p.
1/2(mv^2)=1/2(MV^2).
m.v*v=M.V*V.
if m<M,in order to get same K.E, v>V.
Now,
p.v=P.V (p=m.v & P=M.V).
as v>V, in order to get same K.E,
So, P>p.
(2)
Melkamu said:
6 years ago
Thanks all for explaining.
Hassan rizwi said:
7 years ago
Simple greater the mass greater the momentum.
(1)
Sairohit sandela said:
7 years ago
We know KE=P^2/2m.
For equal KE(kinetic energies).
The Square of P(momentum) is proportional to the mass.
Hence greater the mass greater is the momentum.
For equal KE(kinetic energies).
The Square of P(momentum) is proportional to the mass.
Hence greater the mass greater is the momentum.
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